
Solve Exponential Growth and Decay
Authored by Anthony Clark
Mathematics
9th Grade
CCSS covered

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11 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the a-value (or y-intercept) for the function: f(x) = 800(0.85)x?
800
0.85
0.15
x
Tags
CCSS.HSF-IF.C.7E
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the decay rate for the function: f(x) = 800(0.85)x?
800
0.85
15%
x
Tags
CCSS.HSF-IF.C.8B
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the exponential equation that models this situation?
y = 8(15,000)x
y = 15,000(1.08)x
y = 15,000(0.92)x
y = 15,000(0.08)x
Tags
CCSS.HSF.LE.A.2
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The equation f(x) = 300(1.06)x is being used to calculate the amount of money in a savings account. What does the 1.06 represent?
6% growth
6% decay
1.06% growth
.06% decay
Tags
CCSS.HSF-IF.C.8B
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Determine if the equation y = 15(1.35)x represents exponential growth or decay and justify. Hint: Think about the growth and decay equations.
Growth, because the scale factor is greater than 1
Growth, because the scale factor is less than 1
Decay, because the scale factor is greater than 1
Decay, because the scale factor is less than 1
Tags
CCSS.HSF-IF.C.8B
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Write an exponential function to model the situation. Then solve. The value of a car is $18000 and is depreciating at a rate of 12% per year. What will the value of the car be after 10 years?
V(t) = 18000(.88)t ; $12986.98
V(t) = 18000(.12)t ; $12986.98
V(t) = 18000(.88)t ; $5013.02
V(t) = 18000(.12)t ; $5013.02
Tags
CCSS.HSF.LE.A.2
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the decay factor?
0.08
1.08
0.92
8
Tags
CCSS.HSF-IF.C.8B
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