Algebra II I'm Working Backwards Complex Numbers

Simplify: 
(7 + 2i)(9 - 6i)

• 75-24i

• 63 - 24i  - 12i²

• 51 - 24i

• 58 + 60i

Simplify 
√-25

• -5i

• 5

• 5i

• -5

√-108

• 3i√6

• 3i√20

• 6i√3

• 20i√3

Simplify
3i - (4 + 7i)

• -4 + 10i

• 21 - 12i

• 4 - 10i

• -4 - 4i

• 10
• -10
• 10i
• -10i

Simplify.

5√-18

• -15√2

• 15i√2

• 45i√2

• 3i√2

• 10
• -10
• 10i
• -10i

Refer to the above image, what is the conjugate of the denominator?

• -1 + 5i

• 1 - 5i

• 1 + 5i

• -1 - 5i

Find the sum.
(5-2i) + (-7+8i)

• -2+6i

• 12+6i

• -35-16i²

• -35 -16i

Multiply
(3i)(-2+4i)

• -6+12i

• -12-6i

• -2+7i

• 12+6i