Factor by Grouping, GCF and Trinomials

Factor by grouping:

4p³ + 8p² + 3p + 6

• (2p²+3)(p+2)

• (2p²+6)(p+4)

• (4p²+3)(p+2)

• (4p²+8p)(3p+6)

Factor by grouping:
x³+7x²-2x-14

• (x²-2)(x-7)

• (x²+2)(x-7)

• (x²+2)(x+7)

• (x²-2)(x+7)

3x² - 75

• 3( x + 5 ) ( x - 5 ) 

• Prime

• ( x + 5 ) ( x - 5 ) 

• 3( x - 5 ) ( x - 5 ) 

Tags

CCSS.HSA.APR.C.4

Factor completely: 
3x² + 18x +15
Hint: Factor GCF first.

• 3(x² + 6x + 5)

• (x + 5)(x + 1)

• 3(x + 5)(x + 1)

• Prime

When factoring trinomials by grouping, after you multiply the "a" and the "c" term and identify the "b" term, use these 2 values as clues to find:

• 2 numbers that subtract to "a" times "c" and add to "b"

• 2 numbers that divide to "a" times "c" and add to "b"

• 2 numbers that sum to "a" times "c" and subtract to "b"

• 2 numbers that multiply to "a" times "c" and add to "b"

Factor 5x² -13x - 6

• First, find 2 numbers that multiply to -30 and add to -13.

  a⋅c = 5⋅-6 = -30

  b = -13

• Make 2 groups and factor out the GCF from each group.

  5x( x - 3) + 2(x - 3)

• The 2 numbers are -15 and 2, so use these to break up -13x.

  5x² -15x + 2x + 6

• Write the binomial factors.

  (5x + 2)(x - 3)

To factor a trinomial by grouping, start by...

• multiplying the "a" term times the "c" term and identifying the "b" term

• saying a quick prayer

• multiplying the "b" term times the "c" term and identifying the "a" term

• multiplying the "x" term times the "y" term and identifying the "m" term

To factor the trinomial 6x² + 11x +3, start by multiplying "a" times "c" and identifying "b". Use ax² + bx + c to find these values.

• true

• false

• 9 and -2

• 9 and 2

• -9 and -2

• -9 and 2