Factoring Polynomials by Synthetic Division

For synthetic division, what would be the number in the left hand box?

• 0

• 1

• 2

• 3

Tags

CCSS.HSA.APR.D.6

Is (x-2) a factor of             f(x)= x³-8x²+14x-4?

• Yes, (x-2) is a factor. There is a remainder.

• No, (x-2) is  not a factor. The remainder is zero.

• Yes, (x-2) is a factor. The remainder is zero.

• No, (x-2) is  not a factor. There is a remainder. 

Tags

CCSS.HSA.APR.B.2

Cam divided (x⁴ + 3x² - 4x - 2) by factor of (x-2) using synthetic division. His work is shown above. Which best describes his mistake?

• Cam wrote the remainder incorrectly.

• Cam did not use a zero place holder for the x³ term.

• Cam added instead of subtracting the rows.

• Cam should have used -2 as his division since the factor was x-2.

Tags

CCSS.HSA.APR.D.6

• No

• is

• is not

• Yes

Tags

CCSS.HSA.APR.D.6

Use synthetic division to determine whether the first polynomial is a factor of the second.

• Yes

• is

• No

• is not

Tags

CCSS.HSA.APR.D.6

Use synthetic division to determine whether the first polynomial is a factor of the second.

• No

• is

• is not

• Yes

Tags

CCSS.HSA.APR.D.6

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (2x^4 - 5x^3 + 3x^2 + 4x - 1) by the binomial (x + 1).

• 2x^3 - 7x^2 + 10x - 1

• 2x^3 - 7x^2 + 10x + 6

• 2x^3 - 7x^2 + 10x + 1

• 2x^3 - 7x^2 + 10x - 6

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (2x^3 + 4x^2 - 3x + 1) by the binomial (x - 1).

• 2x^2 + 6x - 3

• 2x^2 + 4x + 3

• 2x^2 + 2x + 3

• 2x^2 + 6x + 3

Tags

CCSS.HSA.APR.D.6

Use synthetic division to divide the polynomial (5x^3 + 2x^2 - 4x + 1) by the binomial (x + 3).

• 5x^2 - 13x + 35 - 104/(x - 3)

• 5x^2 - 13x + 35 + 104/(x + 3)

• 5x^2 - 13x + 35 - 104/(x + 2)

• 5x^2 - 13x + 35 - 104/(x + 3)

Tags

CCSS.HSA.APR.D.6