Dividing Polynomials by Binomials Using Synthetic Division

What is the proper way to write the answer for the following problem?

• 2x³-x²-25x+12

• 2x⁴-x³-25x²-12x+0

• 2x³-x²-25x-12

• 2x⁴-x³-25x²-12x-0

Tags

CCSS.HSA.APR.D.6

What is the next step in synthetic division?

• Multiply the 9 and 6

• Add the 9 and 6

• Bring down the -48

Tags

CCSS.HSA.APR.D.6

Find the quotient:

(2x³ + 5x² + 9) ÷ (x + 3)

• 2x² - x + 3

• 2x³ - x² + 3x

• 2x² + 11x + 33 + 108/x+3

• 2x² - 5x + 12

Tags

CCSS.HSA.APR.D.6

Find the quotient:

(3x³ + 5x - 1) ÷ (x + 1)

• 3x³ - 3x² + 8x - 9

• 3x² - 3x + 8 - 9/x+1

• 3x² + 3x + 8 + 7/x+1

• 3x³ + 3x² + 8x + 7

Tags

CCSS.HSA.APR.D.6

Find the quotient:

(2x³ - 5x - 7) ÷ (x - 2)

• 2x³ - 4x² + 3x - 13

• 2x³ + 4x² +3x - 1

• 2x² - 4x + 3 - 13/x-2

• 2x² + 4x + 3 - 1/x-2

Tags

CCSS.HSA.APR.D.6

• 4x

• 21

• 2x-1

• 10x

Tags

CCSS.HSA.APR.A.1

Find the quotient when (21x² - 52x + 32) is divided by (7x - 8).

• 3x + 4

• 3x + 3

• 3x - 4

• 3x + 2

Tags

CCSS.HSA.APR.D.6

• x+7

• x+2

• X-10

• X-7

Tags

CCSS.HSA.APR.D.6

x+7

y+7

Y-2

2y-q

• x+7

• y+7

• Y-2

• 2y-q

Tags

CCSS.HSA.APR.D.6

• 9

• 8

• 1

• 7

Tags

CCSS.HSA.APR.D.6