Factoring Trinomials by Grouping

To factor 3x² + 14x + 8, find the 2 clue numbers first. Then, use the clue numbers to find the 2 numbers we will use for "bx".

• the 2 numbers that multiply to 24 and add to 14 are 6 and 4.

• the 2 numbers that multiply to 24 and add to 14 are 24 don't exist.

• the 2 numbers that multiply to 24 and add to 14 are 2 and 12.

To factor 2x² +11x + 5, write the middle term using the 2 numbers that multiply to ___ and add to ___, make sure to include the "x". Write it like this:

*Choose 2 that apply.

• 10; 11; 2x² + 5x +2x + 5

• 22; 5; 2x² + 9x +2x + 5

• 10; 11; 2x² + 10x +x + 5

• 10; 11; 2x² + x +10x + 5

To factor 5x² -13x + 6, write the middle term using the 2 numbers that multiply to ___ and add to ___, make sure to include the "x". Write it like this:

*Choose 2 that apply.

• 30; -13; 5x² - 10x - 3x + 6

• 30; -13; 5x² - 2x - 15x + 6

• 30; -13; 5x² - 3x - 10x + 6

• 30; -13; 5x² + 2x + 15x + 6

What 2 numbers should go in the blanks instead of the "bx" term?

• The 2 numbers that multiply to 8 and add to -7, which are 8 and -1.

• The 2 numbers that multiply to -8 and add to -7, which are -8 and -1.

• The 2 numbers that multiply to -8 and add to -7, which are -8 and 1.

What formula do we use to identify the "a", "b", and "c" when factoring?

• ax² +bx + c

• ax² +cx + b

• bx² +ax + c

• cx² +bx + a

Factor
a² - a - 12

• (a - 4)(a + 3)

• (a + 6)(a - 4)

• (a - 6)(a + 4)

• (a + 4)(a - 3)

Factor this trinomial:
x²+10x+16

• (x+2)(x+8)

• (x-2)(x-8)

• (x+1)(x+16)

• (x+6)(x+10)

Factor
x² + 9x - 36

• (x + 12)(x - 3)

• (x + 9)(x - 4)

• (x - 12)(x + 3)

• (x - 9)(x - 4)