Solving Power Equations

Solve 3³ = 3^{4x + 2}

• x = ¼

• x = -¼

• x = ½

• x = -½

To solve 8 = 2^5x+7, you would need to re-write 8 as what base?

• 8

• 4

• 2

• Cannot be determined

Solve: 2^x = 4^x+1

• x = -2

• x = 2

• x = -3

• x = 3

Solve for p:
4^p+2 = 64

• p = -16/9

• p = 1

• p = 8

• p = 7/6

Sovle for x:
5^{-3x - 1} = 25

• x = -1

• x = -4

• x = -3

• x = 1

Solve

• -1/3

• -3

• -1

• 3

Solve for x:
(x + 2)^1/2 - 5 = -2

• 1

• 5

• 7

• 9

Tags

CCSS.HSA.REI.A.2

Rewrite the equation in logarithmic form.

• A

• B

• C

• D

Tags

CCSS.HSF.BF.B.5

Rewrite in exponential form.

• A

• B

• C

• D

Tags

CCSS.HSF.BF.B.5

Rewrite the equation in logarithmic form.

• A

• B

• C

• D

Tags

CCSS.HSF.BF.B.5