Surface Area Prisms Pyramids and Cylinders

Surface Area Prisms Pyramids and Cylinders

7th Grade

17 Qs

quiz-placeholder

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Surface Area Prisms Pyramids and Cylinders

Surface Area Prisms Pyramids and Cylinders

Assessment

Quiz

Mathematics

7th Grade

Hard

Created by

Anthony Clark

FREE Resource

17 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the Surface Area

15m2

16m2

18m2

20m2

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

A square pyramid is covered with decorative wrapping paper with no overlap.  The net of the box is shown on the right.  How many square centimeters of wrapping paper are needed to cover the surfaces of the box? 

108 cm2

324 cm2

180 cm2

432 cm2

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Jesse needs to wrap the present shown below. How much wrapping paper would he need?
How much wrapping paper is needed?

300 in2

558 in2

327 in2

354 in2

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Campbell Soup is creating a new soup label. If a can has a height of 6 in and a diameter of 4 in, how much material does Campbell need for each soup label? Use 3.14 for π.

Is this looking for Lateral or Total surface area?

Lateral

Total

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Jesse needs to wrap the present shown below. How much wrapping paper would he need?

Is this asking for Lateral or Total surface area?

Lateral

Total

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Jesse needs to wrap the present shown below. How much wrapping paper would he need?

Which formula can be used to find the surface area of the present?

SA=Ph+2B

SA=2πrh+2πr2

SA=Ph

V=Bh

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Shelby wants to wrap a present in a box for Sarah. The top and bottom of the box is 8 in. by 3 in., the sides are both 3 in. by 2 in. and the front and back are 8 in. by 2 in. How much wrapping paper will Chloe need to wrap the present?
Which formula could be used to solve for the amount of wrapping paper needed?

SA=Ph+2B

SA=2πrh+2r2

SA=Ph

V=Bh

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