Equations of Polynomials

What equation could represent the graphed polynomial? Assume a is -1 or +1.

• f(x) = - x(x-2)(x+3)

• f(x) = (x-2)(x+3)

• f(x) = - x(x+2)(x-3)

• f(x) = x(x+2)(x-3)

Tags

CCSS.HSA.APR.B.3

What equation could represent the graphed polynomial? Assume a is -1 or +1.

Tags

CCSS.HSA.APR.B.3

What is the equation that represents this polynomial in intercept form? (Hint: you have to find a first)

• y = (x+5)(x-1)

• y = 5(x+5)(x-1)

• y = -(x+5)(x-1)

• y = -5(x+5)(x-1)

Tags

CCSS.HSF-IF.C.7A

Solve x⁴ - 256 = 0

• x = 4, x = - 4

• x = 4, x = 4i

• x = 4, x -4, x = 4i

• x = 4, x -4, x = 4i,         x = -4i

Tags

CCSS.HSA-REI.B.4B

Answer explanation

The roots of the polynomial equation can be found by factoring it as (x-1)(x+2)(x-3)=0, giving x=1, -2, 3 as the solutions.

Tags

CCSS.HSA-REI.B.4B

Solve: -6x-1+5x²=8x²

• x = 5 ±√67 /6

• x = 1, 2/7

• x = 1 ±√ 22

• x = 3 ±√6 / -3

Tags

CCSS.HSA-REI.B.4B

What are the solutions to the polynomial equation?
Choose ALL that apply.

• 2

• -2

• -3

• 3

• a = 0 (repeated)

• a = 1 (repeated)

• a = 1 (repeated), 0 (repeated)

• a = -1 (repeated), 0 (repeated)

Tags

CCSS.HSF-IF.C.7C

Answer explanation

The roots of the polynomial equation can be found by factoring the equation as (x-1)(x+2)(x-3)=0. Therefore, x = 1, -2, 3.

Tags

CCSS.HSA-REI.B.4B