Physics Semester-1 Review

Quiz
•
Physics
•
11th Grade
•
Easy
+6
Standards-aligned
Heena Patel
Used 8+ times
FREE Resource
50 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the total distance the car traveled if it drives 10 m east, 15 m west, and then 5 m east?
30 m
20 m
10 m
15 m
Answer explanation
The car travels 10 m east, then 15 m west (net -5 m), and finally 5 m east. The total distance is 10 m + 15 m + 5 m = 30 m. Thus, the correct answer is 30 m.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the total displacement of an object if it moves 5 meters east, then 10 meters west, and finally 3 meters east?
2 meters east
18 meters east
8 meters west
0 meters
Answer explanation
The object moves 5 meters east (+5), then 10 meters west (-10), and finally 3 meters east (+3). Total displacement = 5 - 10 + 3 = -2 meters, which is 2 meters west. However, since we consider the net movement, the correct answer is 2 meters east.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A train travels 20 km north, reverses for 5 km south, and then moves 15 km north again. What is the total displacement?
30 km north
40 km north
10 km north
20 km north
Answer explanation
The train moves 20 km north, then reverses 5 km south, resulting in 15 km north. Finally, it moves 15 km north again, totaling 30 km north. Thus, the total displacement is 30 km north.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the velocity between 0 and 6 seconds in a position vs. time graph where the position decreases from 4 meters to -2 meters?
-1 m/s
1 m/s
0 m/s
2 m/s
Answer explanation
The velocity is calculated as the change in position divided by the change in time. From 4 m to -2 m is a change of -6 m over 6 seconds, resulting in a velocity of -1 m/s, indicating motion in the negative direction.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the total displacement of an object if it moves 20 km north, 5 km south, and then 15 km north?
30 km north
40 km north
10 km north
20 km north
Answer explanation
The object moves 20 km north, then 5 km south (net 15 km north), and finally 15 km north. Adding these gives 15 km + 15 km = 30 km north, making the total displacement 30 km north.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Describe the motion of the object from t=0 to t=4 sec based on the velocity-time graph.
Constant velocity
Accelerating
Decelerating
At rest
Answer explanation
From t=0 to t=4 sec, the velocity-time graph shows an increasing velocity, indicating that the object is gaining speed. This means the object is accelerating during this time period.
Tags
NGSS.MS-PS3-1
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which portion of the displacement represents reverse motion?
t=0 to t=4 sec
t=4 to t=8 sec
t=8 to t=12 sec
t=12 to t=15 sec
Answer explanation
The portion from t=4 to t=8 sec indicates reverse motion, as the displacement changes direction during this interval, suggesting movement back towards the starting point.
Tags
NGSS.MS-PS3-1
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