Arc Length & Sector Area

Arc Length & Sector Area

Assessment

Flashcard

Mathematics

9th - 11th Grade

Hard

CCSS
HSG.C.B.5, 7.G.B.4, HSF.TF.A.1

+2

Standards-aligned

Created by

Wayground Content

FREE Resource

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14 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the formula for the area of a sector?

Back

The area of a sector is given by the formula: \( A = \frac{\theta}{360} \times \pi r^2 \), where \( \theta \) is the central angle in degrees and \( r \) is the radius.

Tags

CCSS.HSG.C.B.5

2.

FLASHCARD QUESTION

Front

How do you calculate the arc length of a circle?

Back

The arc length \( L \) can be calculated using the formula: \( L = \frac{\theta}{360} \times 2\pi r \), where \( \theta \) is the central angle in degrees and \( r \) is the radius.

Tags

CCSS.HSG.C.B.5

3.

FLASHCARD QUESTION

Front

What is the relationship between the radius and the arc length?

Back

The arc length is directly proportional to the radius; as the radius increases, the arc length increases for a given central angle.

Tags

CCSS.HSG.C.B.5

4.

FLASHCARD QUESTION

Front

If the radius of a circle is 10 cm and the central angle is 90°, what is the arc length?

Back

Using the formula \( L = \frac{\theta}{360} \times 2\pi r \): \( L = \frac{90}{360} \times 2\pi(10) = 15.7 \text{ cm} \) (approximately).

Tags

CCSS.HSG.C.B.5

5.

FLASHCARD QUESTION

Front

What is the area of a sector with a radius of 5 m and a central angle of 60°?

Back

Using the formula \( A = \frac{\theta}{360} \times \pi r^2 \): \( A = \frac{60}{360} \times \pi(5^2) = \frac{25\pi}{3} \text{ m}^2 \) (approximately 26.2 m²).

Tags

CCSS.HSG.C.B.5

6.

FLASHCARD QUESTION

Front

Define a sector in a circle.

Back

A sector is a portion of a circle enclosed by two radii and the arc between them.

7.

FLASHCARD QUESTION

Front

What is the formula for the area of a circle?

Back

The area of a circle is given by the formula: \( A = \pi r^2 \), where \( r \) is the radius.

Tags

CCSS.7.G.B.4

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