
Chem 106 Test 3
Authored by Bowen Cai
Chemistry
University
NGSS covered
Used 1+ times

AI Actions
Add similar questions
Adjust reading levels
Convert to real-world scenario
Translate activity
More...
Content View
Student View
18 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
5 mins • 7 pts
A 100.0 mL sample of 0.18 M HClO4 is titrated with 0.27 M LiOH. Determine the pH of the solution after the addition of 50.0 mL of LiOH.
A 100.0 mL sample of 0.18 M HClO4 is titrated with 0.27 M LiOH. Determine the pH of the solution after the addition of 50.0 mL of LiOH.
3.22
2.35
0.68
1.52
2.
MULTIPLE CHOICE QUESTION
5 mins • 8 pts
A 100.0 mL sample of 0.20 M HF is titrated with 0.10 M KOH. Determine the pH of the solution after the addition of 200.0 mL of KOH. The Ka of HF is 3.5 × 10-4.
A 100.0 mL sample of 0.20 M HF is titrated with 0.10 M KOH. Determine the pH of the solution after the addition of 200.0 mL of KOH. The Ka of HF is 3.5 × 10-4.
9.62
7.00
8.14
3.46
3.
MULTIPLE CHOICE QUESTION
5 mins • 7 pts
A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in NaF. Calculate the pH of the solution after the addition of 100.0 mL of 1.00 M HCl. The Ka for HF is 3.5 × 10-4.
A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in NaF. Calculate the pH of the solution after the addition of 100.0 mL of 1.00 M HCl. The Ka for HF is 3.5 × 10-4.
3.82
3.46
3.09
2.78
Tags
NGSS.HS-PS1-7
4.
MULTIPLE CHOICE QUESTION
2 mins • 4 pts
Strong acids do not make good buffered solutions because
Strong acids dissociate completely and the equilibrium lies far to the right
Strong acids dissociate completely and the equilibrium lies far to the left
Strong acid react completely with any base and the equilibrium lies far to the right
Strong acid react completely with any base and the equilibrium lies far to the left
5.
MULTIPLE CHOICE QUESTION
5 mins • 6 pts
Calculate the pH of a solution of 2.0 M HF when 1.5 M KF is added to it. (Ka for HF = 7.2 x 10-4)
Calculate the pH of a solution of 2.0 M HF when 1.5 M KF is added to it. (Ka for HF = 7.2 x 10-4)
3.14
3.02
3.26
4.02
6.
MULTIPLE CHOICE QUESTION
2 mins • 5 pts
Bromthymol blue, an indicator with a Ka value of 1.0 x 10-7, is yellow in its HIn form and blue in its In- form. Suppose we put a few drops of this indicator in a strongly acidic solution. If the solution is then titrated with NaOH, at what pH will the indicator color change first be visible?
4
5
6
8
7.
MULTIPLE CHOICE QUESTION
5 mins • 8 pts
In the titration of 20.00 mL of 0.500 M CH3COOH with 0.500 M NaOH. (Ka for acetic acid is 1.8 x 10-5).
Calculate the pH at the point in the titration where 7.45 mL of 0.500 M NaOH has been added.
In the titration of 20.00 mL of 0.500 M CH3COOH with 0.500 M NaOH. (Ka for acetic acid is 1.8 x 10-5).
Calculate the pH at the point in the titration where 7.45 mL of 0.500 M NaOH has been added.
4.52
5.46
3.21
4.34
Access all questions and much more by creating a free account
Create resources
Host any resource
Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever
or continue with

Microsoft
%20(1).png)
Apple
Others
Already have an account?