Geometry | Unit 7 | Lesson 1: Lines, Angles, and Curves | Practice Problems

Geometry | Unit 7 | Lesson 1: Lines, Angles, and Curves | Practice Problems

6th Grade

8 Qs

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Geometry | Unit 7 | Lesson 1: Lines, Angles, and Curves | Practice Problems

Geometry | Unit 7 | Lesson 1: Lines, Angles, and Curves | Practice Problems

Assessment

Quiz

Mathematics

6th Grade

Hard

Created by

Illustrative Mathematics

Used 1+ times

FREE Resource

8 questions

Show all answers

1.

OPEN ENDED QUESTION

3 mins • 1 pt

Media Image

Circle with center A. Diameter is drawn. Central angles z and 20 degrees are formed along the diameter. Arc y is opposite central angle z. Arc x is opposite central angle of 20 degrees.

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2.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Media Image

Circle with center A. Diameter B C and G H are drawn. Line segment D F E is drawn with point F on diameter B C. A line is drawn tangent to the circle with point C on the circle.

BC or HG

DE

AB, AC, AG, or AH

3.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Identify whether each statement must be true, could possibly be true, or definitely can’t be true. A diameter is a chord. A radius is a chord. A chord is a diameter. A central angle measures 90°.

must be true

cannot be true

could be true

could be true

4.

OPEN ENDED QUESTION

3 mins • 1 pt

Media Image

Write an equation of the altitude from vertex A.

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5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Triangle ABC has vertices at (5,0), (1,6), and (9,3). What is the point of intersection of the triangle’s medians?

The medians do not intersect in a single point.

(3,3)

(5,3)

(3,4.5)

6.

OPEN ENDED QUESTION

3 mins • 1 pt

Consider the parallelogram with vertices at (0,0), (8,0), (4,6), and (12,6). Where do the diagonals of this parallelogram intersect?

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7.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Media Image

Parallel lines l and p on a coordinate plane, origin O. Points A and B are on line l at A(negative 6 comma 4) and B(2 comma 0). Points F and C are on line p at F(negative 8 comma 2) and C(8 comma negative 6). Point D(2 comma 4) is above line l, and forms triangle A D B with dashed segments. Point E(negative 8 comma negative 6) is below line p, and forms triangle F E C with dashed segments.

Triangle ADB is congruent to triangle CEF.

The slope of line l is equal to the slope of line p.

Triangle ADB is similar to triangle CEF.

sin(A) = sin(C)

cos(B) = sin(C)

8.

OPEN ENDED QUESTION

3 mins • 1 pt

Media Image

Mai wrote a proof that triangle AED is congruent to triangle CEB. Mai's proof is incomplete. How can Mai fix her proof? We know side AE is congruent to side CE and angle A is congruent to angle C. By the Angle-Side-Angle Triangle Congruence Theorem, triangle AED is congruent to triangle CEB.

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