SESION CONICA
Quiz
•
Mathematics
•
10th Grade
•
Medium
ALEXIS LARA
Used 4+ times
FREE Resource
14 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Indica como es y hacia donde habre la parábola cuya ecuación es? : (y - 5)2 = 8 (x +3)
Horizontal, abre hacia la derecha
Vertical, abre hacia la izquierda
Horizontal, abre hacia la izquierda
Vertical, abre hacia le derecha
2.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Halla la ecuación de a parábola con F (2, 3) y D: x = 0
(y + 3)2 = 4 (x - 1)
(x - 3)2 = 4 (y - 1)
(x + 3)2 = 4 (x - 1)
(y - 3)2 = 4 (x - 1)
3.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Halla la ecuación de la parábola cuyo vértice se halla en las coordenadas V (-4, -3) y cuyo foco está en F (-7, -3)
(y - 3) 2 = -12(x + 4)
(y + 3) 2 = -12(x + 4)
(y + 3) 2 = 12(x + 4)
(y + 3) 2 = -12(x - 4)
4.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Dada la ecuación de la parábola x2 - 2x - 8y +33=0 determina la ecuación en la forma canónica.
(y - 1)2 = -8(x - 4)
(x + 1)2 = 8(y - 4)
(x - 1)2 = 8(y - 4)
(y + 1)2 = -8(x - 4)
5.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Convierta la ecuación canónica de la parábola (y + 3)2 = -12(x + 4) a su forma general.
x2 + 12y +6x - 57 = 0
y2 + 6y +12x + 57 = 0
x2 + 6y +12x + 57 = 0
y2 + 12y + 6x + 57 = 0
6.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Encuentra la ecuación de la parábola con Vértice (-1, 2) y Directriz: x = -3
(x + 2)2 = 8(y - 1)
(y - 2)2 = 8(x + 1)
(x - 2)2 = 8(y + 1)
(y + 2)2 = 8(x - 1)
7.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Si se sabe que una parábola con vértice en el origen, tiene su foco en el punto (0, 5), ¿Cuál es la ecuación de su directriz?
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