Molecular Genetics Test 40-80

Molecular Genetics Test 40-80

University

39 Qs

quiz-placeholder

Similar activities

BIOL 101 Exam 4

BIOL 101 Exam 4

University

37 Qs

Forensics: DNA Review

Forensics: DNA Review

11th Grade - University

44 Qs

Topic 2 Lessons 3-5 Test Review #2

Topic 2 Lessons 3-5 Test Review #2

8th Grade - University

37 Qs

MOLECULAR GENETICS (NUCLEIC ACID)

MOLECULAR GENETICS (NUCLEIC ACID)

University

41 Qs

BIOL 221 L14

BIOL 221 L14

University

35 Qs

MicroS03LQ3 - Orthomyxoviridae (Part 1)

MicroS03LQ3 - Orthomyxoviridae (Part 1)

University - Professional Development

38 Qs

Exam 4 Study Guide: DNA Structure and Replication

Exam 4 Study Guide: DNA Structure and Replication

University

41 Qs

DNA Test Review Bio

DNA Test Review Bio

10th Grade - University

34 Qs

Molecular Genetics Test 40-80

Molecular Genetics Test 40-80

Assessment

Quiz

Science

University

Medium

NGSS
HS-LS3-2, HS-LS2-3, HS-LS1-1

+2

Standards-aligned

Created by

Gracie Stevens

Used 8+ times

FREE Resource

39 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Researchers found a strain of E. coli bacteria that had a mutation rates one hundred times higher than normal. Which of the following statements correctly describes the most likely cause of these results?

The single-strand binding proteins were malfunctioning during DNA replication

There were one or more base pair mismatches in the RNA primer

The proofreading mechanism of DNA polymerase was not working properly

The DNA polymerase was unable to add bases to the 3' end of the growing nucleic acid chain

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a healthy eukaryotic cell, the rate of DNA repair is typically equal to the rate of DNA mutation. When the rate of repair lags behind the rate of mutation, what is a possible fate of the cell?

The cell can be transformed into a cancerous cell

RNA may be used instead of DNA as inheritance material

DNA replication will proceed more quickly

DNA replication will continue by a new mechanism

Tags

NGSS.HS-LS3-2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following statements accurately describes the structure of a eukaryotic chromosome?

It is composed of a single strand of DNA

It is constructed as a series of nucleosomes wrapped around two DNA molecules

It has different numbers of genes in different cell types of an organism

It is a single linear molecule of double-stranded DNA plus proteins

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a cell were unable to produce histone proteins, which of the following results would be a likely effect on the cell?

There would be an increase in the amount of DNA produced during replication

The cell's DNA could not be packed into its nucleus

Spindle fibers would not form during prophase

Amplification of other genes would compensate for the lack of histones

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following molecular characteristics cause histones to bind tightly to DNA?

Histones are positively charged, and DNA is negatively charged

Histones are negatively charged, and DNA is positively charged

Both histones and DNA are strongly hydrophobic

Histones are covalently to the DNA

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In DNA replication in E. coli, the enzyme primate is used to attach a 5 to 10 base rib nucleotide strand complementary to the parental DNA strand. The RNA strand serves as a starting point for the DNA polymerase that replicates the DNA. If a mutation occurred in the primase gene, which of the following results would you expect?

Replication would only occur on the leading strand

Replication would only occur on the lagging strand

Replication would not occur on either the leading or lagging strand

Replication would not be affected as the enzyme primase in involved with RNA synthesis

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the basis for the difference in how the leading and lagging strands of DNA molecules are synthesized?

The origins of replication occur only at the 5' end

Helices and single-strand binding proteins work at the 5' end

DNA polymerase can join new nucleotides only to the 3' end of a pre-existing strand, and the strands are antiparallel

DNA ligase works only in the 3' --> 5' direction

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?