Lab Review Quiz (2/12/2024-2/16/2024)

Select the correct code for the following prompt:

Write a function definition that asks the user for their first initial, their last initial, and their age.

DO NOT return anything to the main function.

• int main()

  {

  char firstI, lastI;

  int age;

  printf("Please enter your first initial: ");

  scanf("% c", &firstI);

  printf("\nPlease enter your last initial: ");

  scanf("% c", &lastI);

  printf("\nPlease enter your age: ")

  scanf("%d", age);

  return 0;

  }

• #include <stdio.h>

  void intro();

  int main()

  {

  intro();

  return 0;

  }

  void intro ()

  {

  char firstI, lastI;

  int age;

  printf("Please enter your first initial: ");

  scanf("% c", &firstI);

  printf("\nPlease enter your last initial: ");

  scanf("% c", &lastI);

  printf("\nPlease enter your age: ")

  scanf("%d", age);

  }

• void intro ()

  {

  char firstI, lastI;

  int age;

  printf("Please enter your first initial: ");

  scanf("% c", &firstI);

  printf("\nPlease enter your last initial: ");

  scanf("% c", &lastI);

  printf("\nPlease enter your age: ")

  scanf("%d", age);

  }

• void intro ()

  {

  char firstI, lastI;

  int age;

  printf("Please enter your first initial: ");

  scanf("% c", &firstI);

  printf("\nPlease enter your last initial: ");

  scanf("% c", &lastI);

  printf("\nPlease enter your age: ")

  scanf("%lf", age);

  }

Answer explanation

The function definition shows what the function is doing. The prompt asked us to create a function that asks the user for their first initial, their last initial, and their age. Therefore, we used a series of printf/scanf statements to get this information. The question said that we would not be returning any values back to the main function. Therefore, we need to use a void function. Since the question only asked for the function definition, we do not need to write the entire program.

Select the correct code for the following prompt:

Write a function prototype that asks the user for their first initial, their last initial, and their age. These parameters do not come from the main function.

DO NOT return anything to the main function.

• void intro();

• void intro ()

  {

  char firstI, lastI;

  int age;

  printf("Please enter your first initial: ");

  scanf("% c", &firstI);

  printf("\nPlease enter your last initial: ");

  scanf("% c", &lastI);

  printf("\nPlease enter your age: ")

  scanf("%lf", age);

  }

• intro();

• void intro (char firstI, char lastI, int age);

Answer explanation

The function prototype only includes the function name, the datatype of the variable (if any) that will be returned to the main, and the parameters passed from the main function to the user-defined function. We are told that the function WILL NOT be returning any variables to the main function. Therefore, we know that this will be a void function. We are told that no parameters (variables) are being passed from the main function to our function. Therefore, there is nothing between the parentheses.

How many parameters (variables) are being passed from the main function to the following function:

int KC_won(char scripted, int niners, double purdy, char mahomes);

• 0

• 1

• 2

• 3

• 4

Answer explanation

When passing parameters (variables) from the main function to our function, we put them in the parentheses. There are four variables in the parentheses. Therefore, the answer is four.

What datatype is being returned to the main function?

int KC_won(char scripted, int niners, double purdy, char mahomes);

• char

• double

• int

• I don't know

Answer explanation

When we write the name of the function, we put the datatype of the variable that we will be returning to the main function at the front. So in the following function: int KC_won(char scripted, int niners, double purdy, char mahomes)

the datatype is integer because it says int at the front.

Which of the following is a function prototype?

• #include <stdio.h>

  int main (void)

  {

  return 0;

  }

  int KC_won(char scripted, int niners, double purdy, char mahomes)

  {
  //code goes here

  }

• #include <stdio.h>

  int main (void)

  {

  int ans=KC_won(T, 87, 15.5, S);

  return 0;

  }

• #include <stdio.h>

  int KC_won(char scripted, int niners, double purdy, char mahomes);

  int main (void)

  {

  return 0;

  }

• I don't know

Answer explanation

The function prototype goes before the main function.

What will be displayed to the screen?

int main()

{

int number=4;

if (number%2!=0)

{

printf("This number is odd");

}

else

printf("This number is even");

return 0;

}

• This number is odd.

• This number is even.

• I don't know

Answer explanation

The variable number is equal to 4. This number will be tested against the first condition (number%2!=0) or the remainder of number divided by 2 does not equal zero. Since this is false, the program will print out the printf statement in the else condition.

What will be displayed to the screen?

int main()

{

int avg=65;

if (avg>=90 && avg<=100)

{

printf("A");

}

else if (avg>=80 && avg<90)

{

printf("B");

}

else if (avg>=70 && avg<80)

{

printf("C");

}

else if (avg>=60 && avg<70)

{

printf("D");

}

else

{

printf("F");

}

return 0;

}

• A

• B

• C

• D

• F

Answer explanation

The value of avg is 65. This value will be tested against the if/ else if statements until a statement becomes true.

What will be displayed to the screen?

int main()

{

int noise_db=75;

if (noise_db <= 50)

printf("%d-decibel noise is quiet.\n", noise_db);

else if (noise_db <= 70)

printf("%d-decibel noise is intrusive.\n", noise_db);

else if (noise_db <= 90)

printf("%d-decibel noise is annoying.\n", noise_db);

else if (noise_db <= 110)

printf("%d-decibel noise is very annoying.\n", noise_db);

else

printf("%d-decibel noise is uncomfortable.\n", noise_db);

return 0;

}

• 75-decibel noise is quiet

• 75-decibel noise is intrusive

• 75-decibel noise is annoying

• 75-decibel noise is very annoying

• 75-decibel noise is uncomfortable

Answer explanation

The program will test the value of noise_db against the condition statements from top to down. It will continue to do this until it reaches the condition that is true.

What will be displayed to the screen?

int main()

{

int noise_db=75;

if (noise_db <= 110)

printf("%d-decibel noise is very annoying.\n", noise_db);

else if (noise_db <= 90)

printf("%d-decibel noise is annoying.\n", noise_db);

else if (noise_db <= 70)

printf("%d-decibel noise is intrusive.\n", noise_db);

else if (noise_db <= 50)

printf("%d-decibel noise is quiet.\n", noise_db);

else

printf("%d-decibel noise is uncomfortable.\n", noise_db);

return 0;

}

• 75-decibel noise is very annoying

• 75-decibel noise is annoying

• 75-decibel noise is intrusive

• 75-decibel noise is quiet

• 75-decibel noise is uncomfortable

Answer explanation

The program will test the value of noise_db against the conditions from top to bottom. Since this value is 75, which is less than 110, the program will print out "75-decibel noise is very annoying."

Which series of pairings is correct?

• %c integer, %d double , %lf integer

• %c double, %d integer, %f character

• %c character, %d integer, %f double

• %c character, %d double, %f integer