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Division Methods - Adrian

Authored by Ebony Butler

Mathematics

5th Grade

Division Methods - Adrian
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8 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of 16 divided by 5 using the standard division algorithm?

3 with a remainder of 1

3 with a remainder of 2

4 with a remainder of 1

4 with a remainder of 2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is one advantage of the Method of Partial Quotients for division?

It requires memorization of all multiplication facts

It allows for flexibility in choosing multiples for each step

It always results in fewer steps than the standard method

It can only be used for small divisors

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final answer for 6428 divided by 35 using the Partial Quotients Method?

180 r 28

183 r 28

180 r 23

183 r 23

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main advantage of the Partial Quotients Method for division when dealing with larger divisors?

It can only be used for small divisors

It always results in fewer steps than the standard method

It requires memorization of all multiplication facts

It allows for flexibility in choosing multiples for each step

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of 1276 divided by 26 using the Partial Quotients Method?

49 with a remainder of 2

50 with a remainder of 2

49 with a remainder of 3

50 with a remainder of 3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the best way to get good at math according to the video?

Memorize the multiplication table for all divisors

Use a calculator for all division problems

Only use the traditional division method for all problems

Practice solving several problems on your own

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main advantage of the Partial Quotients Method for division when dealing with larger divisors?

It allows for flexibility in choosing multiples for each step

It requires memorization of all multiplication facts

It always results in fewer steps than the standard method

It can only be used for small divisors

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