EKT 2 Kalkulus

EKT 2 Kalkulus

University

30 Qs

quiz-placeholder

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EKT 2 Kalkulus

EKT 2 Kalkulus

Assessment

Quiz

Mathematics

University

Medium

Created by

Dadang Sujana

Used 28+ times

FREE Resource

30 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 2 pts

Media Image

2.

MULTIPLE CHOICE QUESTION

3 mins • 2 pts

-6

0

2

6

8

Answer explanation

To find the limit, substitute x = -4 into the expression. The numerator becomes (-4)^2 - 6(-4) + 8 = 16 + 24 + 8 = 48. The denominator is -4 - 4 = -8. Thus, the limit is 48 / -8 = -6.

3.

MULTIPLE CHOICE QUESTION

3 mins • 2 pts

3

1

-1

-3

2

Answer explanation

To find \( \lim_{x\rightarrow3}(2x-5) \), substitute \( x=3 \): \( 2(3)-5 = 6-5 = 1 \). Thus, the limit is 1.

4.

MULTIPLE CHOICE QUESTION

3 mins • 2 pts

-1

1

2/3

-1/2

-3/2

Answer explanation

To find the limit as x approaches 1, substitute x=1 into the expression. The numerator becomes 0 and the denominator also becomes 0, indicating an indeterminate form. Factor the expression: (x-1)(x-4)/(x-1)(x+1). Cancel (x-1) and evaluate the limit, yielding -3/2.

5.

MULTIPLE CHOICE QUESTION

3 mins • 2 pts

6x-4

3x^2-4

6x-4x

6x^2-4

3x^2-4x

Answer explanation

Untuk menghitung turunan dari f(x)=3x^2-4x+5, gunakan aturan turunan. Turunan dari 3x^2 adalah 6x, dan turunan dari -4x adalah -4. Jadi, turunan f(x) adalah 6x-4, yang merupakan pilihan yang benar.

6.

MULTIPLE CHOICE QUESTION

3 mins • 2 pts

12x^2-12x+2

12x^2-12x-2

12x^2-12x

12x^3-12x^2+2

12x^3-12x^2-2

Answer explanation

Untuk menghitung turunan g(x)=4x^3-6x^2+2x-9, gunakan aturan turunan. Turunan dari 4x^3 adalah 12x^2, dari -6x^2 adalah -12x, dari 2x adalah 2, dan turunan dari -9 adalah 0. Jadi, g'(x) = 12x^2 - 12x + 2.

7.

MULTIPLE CHOICE QUESTION

3 mins • 2 pts

Jika f(x)= x3 + 8x, Carilah f’(c)

3c^2 + 8

c^2 + 8

c^3 + 8

3c^2 - 8

2c^2 + 8

Answer explanation

Untuk mencari f'(c), kita harus menghitung turunan dari f(x) = x^3 + 8x. Turunan f'(x) adalah 3x^2 + 8. Jadi, f'(c) = 3c^2 + 8, yang merupakan pilihan yang benar.

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