Estimate the vancomycin clearance (in L/hr) for a 60-year-old patient who weighs 70 kg and has a creatinine clearance 75 mL/min. Round to the nearest hundredth.
ClVanc (L/hr)= [0.69*(CrCl) + 3.66] x 0.06
PK Module 14: In-Class Activity 1
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Marcy Hernick
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1.
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1 min • 1 pt
Estimate the vancomycin clearance (in L/hr) for a 60-year-old patient who weighs 70 kg and has a creatinine clearance 75 mL/min. Round to the nearest hundredth.
ClVanc (L/hr)= [0.69*(CrCl) + 3.66] x 0.06
Answer explanation
ClVanc (L/hr)= [0.69*(CrCl) + 3.66] x 0.06
ClVanc (L/hr)= [0.69*(75) + 3.66] x 0.06
ClVanc (L/hr)= 3.32
2.
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1 min • 1 pt
After administration of the loading dose and seven doses (1500 mg each) at 12-hour intervals, plasma vancomycin concentrations are determined to be 44 mg/L (2 hours after the end of the 2-hour infusion) and 16 mg/L at the end of the dosing interval.
What is the half-life of vancomycin (in hr) in this patient?
Answer explanation
Ke = ln (C1/C2)/t2-t1
K = ln (44mg/L/16mg/L) / (12 - 4 hr) = 0.126 hr-1
t1/2 = 0.693/K = 0.693/0.126 = 5.5 hr
3.
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2 mins • 1 pt
Calculate the Ke (in hr-1) for a patient that will be initiated on vancomycin using the equation Ke = 0.00083/hr x CrCl + 0.0044 for a 45-year-old man, 5' 10'' tall, weighing 73 kg (IBW = 73 kg), serum creatinine concentration of 1.00 mg/dL.
Ke = 0.00083/hr x CrCl + 0.0044
Answer explanation
Step 1: Calculate CrCl
CrCl = (140-45)(73)/(72 x 1) = 96.3 mL/min
Step 2: Calculate Ke
Ke = 0.00083/hr x CrCl + 0.0044 = 0.00083/hr(96.3) + 0.0044 = 0.084 hr-1
4.
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1 min • 1 pt
BW, a 42-year-old man, 5' 10'' tall, weighing 75 kg (IBW = 73 kg), needs to receive a loading dose of vancomycin (25 mg/kg) that will be infused over 2 hours.
Calculate the loading dose for this patient in mg. For grading purposes do not round.
Answer explanation
LD = 25 mg/kg x 75 kg = 1875 mg
5.
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1 min • 1 pt
A patient is receiving 750 mg of vancomycin every 12 hours by 1-hour infusion. A steady state trough concentration is measured 0.5 hours before a dose and reported as 12 mg/L. You wish to raise the trough to 17.5 mg/L.
What dose (rounded to nearest mg) would you suggest if the interval would remain at 12 hours?
Answer explanation
Set up a ratio
Dose1/Conc1 = Dose 2/Conc2
750/12 = Dose2/17.5
Dose = 1094 mg
6.
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1 min • 1 pt
A patient is receiving 750 mg of vancomycin every 12 hours by 1-hour infusion. A steady state trough concentration is measured 0.5 hours before a dose and reported as 12 mg/L. You wish to raise the trough to 17.5 mg/L.
What dosing interval should you use if you wish to keep the dose at 750 mg? Do not round
Answer explanation
Taunew = (Css old)/(Css new) x Tau old
Taunew = (12/17.5) x 12 hr
Taunew = 8.2 hours Round to 8 hours
7.
FILL IN THE BLANK QUESTION
2 mins • 1 pt
E.K., a 60-year-old, 50-kg woman with a serum creatinine of 1.0 mg/dL, has been empirically started on 750 mg of vancomycin every 12 hours. A culture indicates that the infection is caused by MRSA with an MIC of 1.0 mg/L. Design a dose in mg to be administered every 24 hr that will produce therapeutic vancomycin concentrations and an AUC24/MIC ≥ 400 for E.K. You have calculated her patient specific K = 0.054 hr-1 and Vd = 34.8 L.
AUC24/MIC = X24 / (Cl x MIC)
Answer explanation
Step 1: Calculate Cl
Cl = V x K = 34.8 L x 0.054 hr-1 = 1.88 L/hr
Step 2: Calculate Dose
Dose24hr = AUC24/MIC x Cl x MIC
Dose24hr = 400 x 1.88 x 1 = 752 mg
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