Rotasi 1

Rotasi 1

12th Grade

10 Qs

quiz-placeholder

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Rotasi 1

Rotasi 1

Assessment

Quiz

Mathematics

12th Grade

Medium

CCSS
8.G.A.3, HSG.CO.A.2, HSF-IF.C.7E

+1

Standards-aligned

Created by

Suwaryanto Junaedi

Used 2+ times

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 10 pts

Pada rotasi sebuah titik  P(3, 4) sejauh 90 derajat berlawanan arah jarum jam terhadap titik pusat  O(0, 0), koordinat baru titik P adalah...

(-3,-4)

(-4,3)

(4,3)

(3,4)

(-4,3)

2.

MULTIPLE CHOICE QUESTION

1 min • 10 pts

Titik A(2, 5) dirotasi sejauh 180 derajat terhadap titik pusat O(0, 0) . Koordinat baru titik A adalah...

(-5,-2)

(5,-2)

(2,-5)

(-2,-5)

(5,2)

Tags

CCSS.8.G.A.3

CCSS.HSG.CO.A.5

3.

MULTIPLE CHOICE QUESTION

1 min • 10 pts

Titik B(1, 3) dirotasi sejauh 270 derajat searah jarum jam terhadap titik pusat O(0, 0) . Koordinat baru titik B adalah...

(3,-1)

(-3,1)

(1,3)

(-1,3)

(-1,-3)

Tags

CCSS.8.G.A.3

CCSS.HSG.CO.A.5

4.

MULTIPLE CHOICE QUESTION

1 min • 10 pts

Titik C(4, -2) dirotasi sejauh 45 derajat berlawanan arah jarum jam terhadap titik pusat O(0, 0). Koordinat baru titik C adalah...

(2√2+√2, 2√2-√2)

(2√2+√2, 2√2+√2)

(2√2-√2, 2√2+√2)

(2√2, -2√2)

( √2 , 2√2)

Tags

CCSS.HSG.CO.A.2

5.

MULTIPLE CHOICE QUESTION

1 min • 10 pts

Titik D(6, -4) dirotasi sejauh 60 derajat searah jarum jam terhadap titik pusat O(0, 0) . Koordinat baru titik D adalah...

( 3+√3 , 3√3-2)

( 3 -2√3 , 3√3-2)

( 3+2√3 , 3√3-2)

( 3+2√3 , 3√3+2)

( 3-2√3 , 3√3)

Tags

CCSS.8.G.A.3

CCSS.HSG.CO.A.5

6.

MULTIPLE CHOICE QUESTION

1 min • 10 pts

Sebuah garis lurus dengan persamaan y = 2x + 3 dirotasi sejauh 90 derajat berlawanan arah jarum jam. Persamaan garis hasil rotasi adalah...

2x +y -3 = 0

2x - y + 3 = 0

x + 3y - 2 = 0

x +2y -3 = 0

x -2y + 4 = 0

7.

MULTIPLE CHOICE QUESTION

1 min • 10 pts

Sebuah garis lurus dengan persamaan y = x2 - 3x - 4 dirotasi sejauh 90 derajat searah arah jarum jam. Persamaan garis hasil rotasi adalah...

x = y2 - 3y - 4

x = -y2 + 3y + 4

y = x2 + 3x + 4

y = x2 - 3x - 4

y = x2 + 3x + 4

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