Arah dari vektor A B → \overrightarrow{AB} A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> adalah...

( − 4 , 2 ) \left(-4,2\right) ( − 4 , 2 )

( 4 , − 2 ) \left(4,-2\right) ( 4 , − 2 )

( 4 , 2 ) \left(4,2\right) ( 4 , 2 )

( − 4 , − 2 ) \left(-4,-2\right) ( − 4 , − 2 )

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b ⃗ = − i + 3 j + 7 k d a n b⃗=-i+3j+7k\ dan\ b ⃗ = − i + 3 j + 7 k d a n c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ − b ⃗ + c ⃗ ! c⃗=5i-2j-k\ Tentukan\ a⃗-b⃗+c⃗! c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ − b ⃗ + c ⃗ !

( 8 , 0 , − 4 ) \left(8,0,-4\right) ( 8 , 0 , − 4 )

( − 8 , 0 , − 4 ) \left(-8,0,-4\right) ( − 8 , 0 , − 4 )

( 6 , 0 , − 4 ) \left(6,0,-4\right) ( 6 , 0 , − 4 )

( − 6 , 0 , − 4 ) \left(-6,0,-4\right) ( − 6 , 0 , − 4 )

( 6 , 0 , 4 ) \left(6,0,4\right) ( 6 , 0 , 4 )

Jika p → = 5 i − 4 j + 3 k \overrightarrow{p}=5i-4j+3k p <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 5 i − 4 j + 3 k , q → = 2 i + 7 k \overrightarrow{q}=2i+7k q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 2 i + 7 k , r → = 6 j − 2 k \overrightarrow{r}=6j-2k r <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 6 j − 2 k Nilai dari p → . ( q → + r → ) \overrightarrow{p}\ .\ \left(\overrightarrow{q}\ +\overrightarrow{r}\right) p <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> . ( q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + r <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> )

D. − 38 i − 19 j + 38 k -38i-19j+38k − 3 8 i − 1 9 j + 3 8 k

A. − 38 i − 19 j − 38 k -38i-19j-38k − 3 8 i − 1 9 j − 3 8 k

B. 19 i − 39 j + 38 k 19i-39j+38k 1 9 i − 3 9 j + 3 8 k

D. 38 i + 19 j + 38 k 38i+19j+38k 3 8 i + 1 9 j + 3 8 k

E. 38 i − 39 j + 19 k 38i-39j+19k 3 8 i − 3 9 j + 1 9 k

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b → = − 𝑖 + 3 𝑗 + 7 𝑘 d a n c → = 5 𝑖 − 2 𝑗 − 𝑘 \overrightarrow{b}=−𝑖+3𝑗+7𝑘\ dan\ \ \overrightarrow{c}=5𝑖−2𝑗−𝑘 b <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − i + 3 j + 7 k d a n c <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 5 i − 2 j − k T e n t u k a n a ⃗ − c ⃗ ! Tentukan\ a⃗-c⃗! T e n t u k a n a ⃗ − c ⃗ !

( − 3 , 7 , 5 ) (-3,7,5) ( − 3 , 7 , 5 )

( − 3 , 7 , − 5 ) (-3,7,-5) ( − 3 , 7 , − 5 )

( 3 , 7 , 5 ) (3,7,5) ( 3 , 7 , 5 )

( 7 , 7 , 3 ) \left(7,7,3\right) ( 7 , 7 , 3 )

( − 7 , 7 , 3 ) \left(-7,7,3\right) ( − 7 , 7 , 3 )

Tentukan Vektor-Vektor pada Gambar 2 dalam ungkapan Vektor satuan

∣P∣=3i+3j dan ∣Q∣=-5i-3j

∣P∣=3i-3j dan ∣Q∣=-5i+3j

∣P∣=3i+3j dan ∣Q∣=-5i-3j

∣P∣=-3i+3j dan ∣Q∣=5i+3j

∣P∣=-3i-3j dan ∣Q∣=-5i-3j

Jika u ‾ = ( 3 , − 5 ) \overline{u}=\left(3,-5\right) u = ( 3 , − 5 ) dan v ‾ = ( − 4 , − 1 ) \overline{v}=\left(-4,-1\right) v = ( − 4 , − 1 ) . Nilai 2 u ‾ − v ‾ = ⋅ ⋅ ⋅ 2\overline{u}-\overline{v}=\cdot\cdot\cdot 2 u − v = ⋅ ⋅ ⋅

( 10 , − 9 ) \left(10,-9\right) ( 1 0 , − 9 )

( − 1 , − 6 ) \left(-1,-6\right) ( − 1 , − 6 )

( 7 , − 4 ) \left(7,-4\right) ( 7 , − 4 )

( 2 , − 11 ) \left(2,-11\right) ( 2 , − 1 1 )

( 11 , − 3 ) \left(11,-3\right) ( 1 1 , − 3 )

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b ⃗ = − i + 3 j + 7 k d a n b⃗=-i+3j+7k\ dan b ⃗ = − i + 3 j + 7 k d a n c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ + b ⃗ ! c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗! c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ + b ⃗ !

i ‾ + 8 j ‾ + 11 k ‾ \overline{i}+8\overline{j}+11\overline{k} i + 8 j + 1 1 k

3 i ‾ + 8 j ‾ + 11 k ‾ 3\overline{i}+8\overline{j}+11\overline{k} 3 i + 8 j + 1 1 k

3 i ‾ − 8 j ‾ + 11 k ‾ 3\overline{i}-8\overline{j}+11\overline{k} 3 i − 8 j + 1 1 k

i ‾ − 8 j ‾ + 11 k ‾ \overline{i}-8\overline{j}+11\overline{k} i − 8 j + 1 1 k

− i ‾ + 8 j ‾ + 11 k ‾ -\overline{i}+8\overline{j}+11\overline{k} − i + 8 j + 1 1 k

vektor

Authored by tukang belajar

Mathematics

10th Grade

CCSS covered

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

Content View

Student View

20 questions

Show all answers

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Diketahui vektor-vektor $\overrightarrow{a\ }=-2i-1j+8k$ dan $\overrightarrow{b\ }=-22i+9j-2k$ , panjang vektor $\overrightarrow{b}+\overrightarrow{a}$ adalah ... .

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Besar resultan dari vektor $\overrightarrow{p\ }=\ \left(_{\ 23}^{\ \ 8}\right)$ dan $\overrightarrow{q\ }=\left(_{-2}^{12}\right)$ adalah ... .

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Jika besar sudut antara vektor $\overrightarrow{p}=-2\overrightarrow{i}-1\overrightarrow{j}+3\overrightarrow{k}$ dan $\overrightarrow{q}=1\overrightarrow{i}-3\overrightarrow{j}+2\overrightarrow{k}$ adalah $\alpha$ , maka besar $\alpha$ adalah ... $\degree$ . (Jawab hanya dengan angka saja)

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Diketahui vektor-vektor $\overrightarrow{a\ }=-2\overrightarrow{i\ }-1\overrightarrow{j}+8\overrightarrow{k}$ dan $\overrightarrow{b\ }=-22\overrightarrow{i}+9j-2\overrightarrow{k}$ , panjang vektor $\overrightarrow{b}+\overrightarrow{a}$ adalah ... .

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

(-1,12)

(-7,-2)

(-7,2)

(7,2)

(1,-12)

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Diketahui\ ā=(2,0,-2)\ \ dan\$ $ū=(1,-1,1).$
$Tentukan\ \ \ ā-ū!$

$(1,-1,-3)$

$(1,-1,3)$

$(-1,-1,3)$

$(-1,1,-3)$

$(-1,-1,-3)$

$Tentukan\ vektor\ basis\ (OA)⃗!$

$(2,5,3)$

$(2,-5,3)$

$(2,-5,-3)$

$(-2,-5,3)$

$(-2,-5,-3)$

Arah dari vektor $\overrightarrow{AB}$ adalah...

$\left(4,-2\right)$

$\left(4,2\right)$

$\left(-4,-2\right)$

$\left(-4,2\right)$

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

16 questions

Tổng hiệu của vecto, tích một số với một vecto

Quiz

•

10th Grade

15 questions

Circles Review (Module 10)

Quiz

•

9th - 10th Grade

20 questions

Ulangan Vektor II

Quiz

•

10th Grade

20 questions

Topic 3 - Polynomial Functions

Quiz

•

9th - 12th Grade

17 questions

Revision

Quiz

•

10th Grade - University

16 questions

Diagnostico Senior 4

Quiz

•

10th Grade

18 questions

BÀI TẬP SỐ PHỨC

Quiz

•

8th - 12th Grade

15 questions

4.5 & 4.6 Review

Quiz

•

9th - 12th Grade

Popular Resources on Wayground

7 questions

History of Valentine's Day

Interactive video

•

4th Grade

15 questions

Fractions on a Number Line

Quiz

•

3rd Grade

20 questions

Equivalent Fractions

Quiz

•

3rd Grade

25 questions

Multiplication Facts

Quiz

•

5th Grade

$fractions$

22 questions

fractions

Quiz

•

3rd Grade

15 questions

Valentine's Day Trivia

Quiz

•

3rd Grade

20 questions

Main Idea and Details

Quiz

•

5th Grade

20 questions

Context Clues

Quiz

•

6th Grade

Discover more resources for Mathematics

10 questions

Elijah McCoy: Innovations and Impact in Black History

Interactive video

•

6th - 10th Grade

10 questions

Factor Quadratic Expressions with Various Coefficients

Quiz

•

9th - 12th Grade

5 questions

Triangle Congruence Theorems

Interactive video

•

9th - 12th Grade

15 questions

Module 3 Topic 1 Vocabulary Quiz

Quiz

•

10th Grade

16 questions

Circle Vocabulary

Quiz

•

9th - 10th Grade

15 questions

Exponential Growth and Decay Word Problems Practice

Quiz

•

9th - 12th Grade

10 questions

Multiplying Fractions with Area Models

Interactive video

•

6th - 10th Grade

10 questions

Adding and Subtracting Fractions with Unlike Denominators

Interactive video

•

6th - 10th Grade

vektor

Diketahui vektor-vektor a →=−2i−1j+8k\overrightarrow{a\ }=-2i-1j+8ka =−2i−1j+8k dan b →=−22i+9j−2k\overrightarrow{b\ }=-22i+9j-2kb =−22i+9j−2k , panjang vektor b→+a→\overrightarrow{b}+\overrightarrow{a}b+a adalah ... .

Besar resultan dari vektor p →= ( 23 8)\overrightarrow{p\ }=\ \left(_{\ 23}^{\ \ 8}\right)p ​= ( 23 8​) dan q →=(−212)\overrightarrow{q\ }=\left(_{-2}^{12}\right)q ​=(−212​) adalah ... .

Diketahui aˉ=(2,0,−2) dan Diketahui\ ā=(2,0,-2)\ \ dan\ Diketahui aˉ=(2,0,−2) dan uˉ=(1,−1,1).ū=(1,-1,1).uˉ=(1,−1,1). Tentukan aˉ−uˉ!Tentukan\ \ \ ā-ū!Tentukan aˉ−uˉ!

Tentukan vektor basis (OA)⃗!Tentukan\ vektor\ basis\ (OA)⃗!Tentukan vektor basis (OA)⃗!

Arah dari vektor AB→\overrightarrow{AB}AB adalah...

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Diketahui vektor-vektor $\overrightarrow{a\ }=-2i-1j+8k$ dan $\overrightarrow{b\ }=-22i+9j-2k$ , panjang vektor $\overrightarrow{b}+\overrightarrow{a}$ adalah ... .

Besar resultan dari vektor $\overrightarrow{p\ }=\ \left(_{\ 23}^{\ \ 8}\right)$ dan $\overrightarrow{q\ }=\left(_{-2}^{12}\right)$ adalah ... .

$Diketahui\ ā=(2,0,-2)\ \ dan\$ $ū=(1,-1,1).$
$Tentukan\ \ \ ā-ū!$

$Tentukan\ vektor\ basis\ (OA)⃗!$

Arah dari vektor $\overrightarrow{AB}$ adalah...