Synthetic Division

(2x³ + 5x² + 9) ÷ (x + 3)

• 2x² - x + 3
• 2x³ - x² + 3x
• 2x² + 11x + 33 + 108/x+3
• 2x² - 5x + 12

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.D.6

(3x³ + 5x - 1) ÷ (x + 1)

• 3x³ - 3x² + 8x - 9
• 3x² - 3x + 8 - 9/x+1
• 3x² + 3x + 8 + 7/x+1
• 3x³ + 3x² + 8x + 7

Tags

CCSS.HSA.APR.D.6

-2x²+4x+48 ÷ x+4

• -2x+12
• 2x+12
• -4x+9
• 4x+9

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

x²-6x+8 ÷ x-2

• x-6
• x-9 R=2
• x-4
• x-8 R=3

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.D.6

(3x³ - 2x² - 7x + 6) ÷ (x + 1)

• 3x³ - 5x² - 2x + 8
• 3x² + x - 6
• 3x² - 5x - 2 + 8/x+1
• 3x³ + x² - 6x

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.D.6

If you were dividing x⁶ + 4x³ + 2, how many 0's would you need when setting up the top row of your synthetic division?

• 0
• 2
• 4
• 6

For synthetic division, what would be the number in the left hand box?

• 0
• 1
• 2
• 3

Tags

CCSS.HSA.APR.B.2

Which term is missing in this problem?
2x³ + 5x² + 9 ÷
x + 3

• x⁴
• x³
• x²
• x

Tags

CCSS.HSA.APR.D.6

If you are missing an exponent in your polynomial you must put a zero as a coefficient place holder for that exponent

• True
• False

Tags

CCSS.HSA.SSE.A.2

What is the proper way to write the answer for the following problem?

• 2x³-x²-25x+12

• 2x⁴-x³-25x²-12x+0

• 2x³-x²-25x-12

• 2x⁴-x³-25x²-12x-0

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3