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ตรีโกณมิติ

Authored by บงกช โคตรมุงคุณ

Mathematics

University

Used 12+ times

ตรีโกณมิติ
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10 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

กำหนดให้ sin x =  13\frac{1}{3}  จงหาค่าของ sin ( π\pi  + x )

 13-\frac{1}{3}  

 13\frac{1}{3}  

 222-\frac{2\sqrt{2}}{2}  

 222\frac{2\sqrt{2}}{2}  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

กำหนดให้ cos x =  23\frac{2}{3}   จงหาค่าของ cos ( π\pi  +x )

 23-\frac{2}{3}  

 23\frac{2}{3}  

 53-\sqrt{\frac{5}{3}}  

 53\sqrt{\frac{5}{3}}  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

กำหนดให้ tan x =  12\frac{1}{2}  ​ จงหาค่าของ ( π\pi  +x )

-2

2

 12\frac{1}{2}  

 12-\frac{1}{2}  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

กำหนดให้ sinθ = -cos θ\theta  เมื่อ  πθ2π\pi\le\theta\le2\pi  จงหาค่าของ θ

 7π4\frac{7\pi}{4}  

 5π4\frac{5\pi}{4}  

 7π6\frac{7\pi}{6}  

 5π3\frac{5\pi}{3}  

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 3-\sqrt{3}  กำหนดให้ sin θ\theta  =  cosθ เมื่อ π2θ3π2\frac{\pi}{2}\le\theta\le\frac{3\pi}{2}  จงหาค่าของθ

 5π6\frac{5\pi}{6}  

 7π6\frac{7\pi}{6}  

 2π3\frac{2\pi}{3}  

 4π3\frac{4\pi}{3}  

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

กำหนดให้ cos θ =  3 \sqrt{3\ }  sin θ\theta  เมื่อ  πθ2π\pi\le\theta\le2\pi  จงหาค่าของ θ\theta  

 11π6\frac{11\pi}{6}  

 7π6\frac{7\pi}{6}  

 4π3\frac{4\pi}{3}  

 5π3\frac{5\pi}{3}  

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

จงหาค่าของ sec  11π4\frac{11\pi}{4}  

 22-\frac{\sqrt{2}}{2}  

 22\frac{\sqrt{2}}{2}  

 2\sqrt{2}  

 2-\sqrt{2}  

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