Acid-Base

Acid-Base

11th - 12th Grade

10 Qs

quiz-placeholder

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Acid-Base

Acid-Base

Assessment

Quiz

Chemistry

11th - 12th Grade

Practice Problem

Hard

Created by

Mohamad Fakih

Used 9+ times

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10 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

which of the following formulas could be used to find the  [OH] \left[OH^-\right]\  at equilibrium for weak base problems? knowing that weak base ionizes by less than 5%. 

 logKb.[weak base]0-\log\sqrt{K_b.\left[weak\ base\right]_0}  

 Ka. [weak base]0\sqrt{K_a.\ \left[weak\ base\right]_0}  

 logKa. [weak acid]0-\log\sqrt{K_a.\ \left[weak\ acid\right]_0}  

 Kb.[weak base]0\sqrt{K_b.\left[weak\ base\right]_0}  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

which of the following formulas could be used to find the [H+] at equilibrium for WEAK ACID problems? assuming that this weak acid will ionize by less than 5%.

logKa.[weak acid]0-\log\sqrt{K_a.\left[weak\ acid\right]_0}

Ka.[weak acid]0\sqrt{K_a.\left[weak\ acid\right]_0}

Kb.[weak base]0\sqrt{K_b.\left[weak\ base\right]_0}

Ka.[weak base]0\sqrt{K_a.\left[weak\ base\right]_0}

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What does 5% Rule mean?

when you carry out a calculation that does not drop the 'minus x' from the denominator while finding pH of weak acid or base.

when you use the approximation method that drops the 'minus x' from the denominator while finding pH of weak acid or base assuming that the weak acid or base dissociates by MORE than 5%.

when you use the approximation method that drops the 'minus x' from the denominator while finding pH of weak acid or base assuming that the weak acid or base dissociates by LESS than 5%.

When you have a strong acid that dissociates by more than 5%.

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

If the concentration of strong monoprotic acid is given (HA) how could you find the  [H+]\left[H^+\right] in the solution.

 [H+] = [HA]0\left[H^+\right]\ =\ \left[HA\right]_0  

 [H+] =2 .[HA]0\left[H^+\right]\ =2\ .\left[HA\right]_0  

 [H+] = [HA]0X\left[H^+\right]\ =\ \left[HA\right]_0-X  

 [H+] = [HA]02\left[H^+\right]\ =\ \frac{\left[HA\right]_0}{2}  

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

If the concentration of  Sr(OH)2Sr\left(OH\right)_2 is given, how could you find the  [OH]\left[OH^-\right] in the solution? 

 [OH]=[Sr(OH)2]0\left[OH^-\right]=\left[Sr\left(OH\right)_2\right]_0  

 [OH]=[Sr(OH)2]02\left[OH^-\right]=\frac{\left[Sr\left(OH\right)_2\right]_0}{2}  

 [OH]=[Sr(OH)2]0 +2\left[OH^-\right]=\left[Sr\left(OH\right)_2\right]_0\ +2  

 [OH]=2. [Sr(OH)2]0\left[OH^-\right]=2.\ \left[Sr\left(OH\right)_2\right]_0  

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which formula is related to the percent ionization of weak acids?

[weak acid]0 [H+]at equilibrium x100\frac{\left[weak\ acid\right]_0\ }{\left[H^+\right]_{at\ equilibrium\ }}x100

[weak acid]0100 x [H+]\frac{\left[weak\ acid\right]_0}{100\ x\ \left[H^+\right]}

[H+]at equilibrium [weak acid]0 x100\frac{\left[H^+\right]_{at\ equilibrium\ }}{\left[weak\ acid\right]_0\ }x100

[H+]at equilibrium x 100\sqrt{\left[H^+\right]_{at\ equilibrium\ }\ x\ 100}

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

which of the following statement  is NOT correct?

As  KaK_a  value increases  pKapK_a  value decreases the stronger the acid is. 

As  KaK_a  value decreases  pKapK_a  value decreases the weaker the acid is. 

As  pKapK_a  value increases  KaK_a  value decreases the weaker the acid is.

The higher the  KaK_a  the lower the  KbK_b  

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