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Oblique Triangles (Law of Sines)

Authored by gemalyn awingan

Mathematics

9th - 10th Grade

Used 9+ times

Oblique Triangles (Law of Sines)
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Using the law of sines, which expression is equivalent to  \frac{b}{\sin\ B}   ?

 asin A\frac{a}{\sin\ A}  

 ac\frac{a}{c}  

 sin Aa\frac{\sin\ A}{a}  

 csinA \frac{c}{\sin A\ }  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In triangle ABC, which expression is equal to b?

sin AasinB\frac{\sin\ A}{a\sin B}

c sin Bsin B\frac{c\ \sin\ B}{\sin\ B}

asinBsinA\frac{a\sin B}{\sin A}

sin Cc sin B\frac{\sin\ C}{c\ \sin\ B}

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The law of sines cannot be used to solve a triangle if

three sides are given.

two angles and a side are given.

the given triangle is a right triangle.

two sides and an angle opposite one of them are given.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If we are given sides a and c along with angle A, which of the following can be found by using the law of sines?

side b

angle B

angle C

side b, angle B and angle C

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For any triangle ABC, which of the following is not true?

sin Aa=sin Bb\frac{\sin\ A}{a}=\frac{\sin\ B}{b}

sin Asin B=ab\frac{\sin\ A}{\sin\ B}=\frac{a}{b}

bsin A = a sin Bb\sin\ A\ =\ a\ \sin\ B

asin A = b sin Ba\sin\ A\ =\ b\ \sin\ B

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

For the given triangle ABC,  \angle C  can be found by using the equation 

 sin C = 98\sin\ C\ =\ \frac{9}{8}  

 sin C = 89\sin\ C\ =\ \frac{8}{9}  

 bsin 300= 9sin C\frac{b}{\sin\ 30^0}=\ \frac{9}{\sin\ C}  

 9sin C=8sin 300\frac{9}{\sin\ C}=\frac{8}{\sin\ 30^0}  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many non-congruent triangles ABC can be formed if c = 5 , A = 60o , and a = 8?

none

one

two

three

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