Dado los vectores de la figura, si se sabe que v → = u → − t → + w → \overrightarrow{v\ }=\ \overrightarrow{u\ }-\ \ \overrightarrow{t\ \ }+\ \ \overrightarrow{w\ } v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − t <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + w <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> ,¿ cuál es la magnitud del vector v → \overrightarrow{v\ } v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> ?

58 \sqrt{58} 5 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

74 \sqrt{74} 7 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

53 \sqrt{53} 5 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

34 \sqrt{34} 3 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

El triángulo ABC de la figura adjunta, es rectángulo en C. Si CD es la altura respecto de la hipotenusa, AC = 6 cm y BC = 12 cm , entonces la medida de AD es :

6 5 5 \frac{6}{5}\sqrt{5} 5 6 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 5 6\sqrt{5} 6 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 5 3\sqrt{5} 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 5 2\sqrt{5} 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 5 \frac{2}{3}\sqrt{5} 3 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

En la figura, ¿cuál es la medida de DB ?

2 5 5 c m \frac{2\sqrt{5}}{5}\ cm 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

5 c m \sqrt{5}cm 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

3 5 5 c m \frac{3\sqrt{5}}{5}\ cm 5 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

3 5 2 c m \frac{3\sqrt{5}}{2}\ cm 2 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

2 5 3 c m \frac{2\sqrt{5}}{3}\ cm 3 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

En el triángulo ABC, rectángulo en C, AB = 20 cm y AD = 4 cm. La medida de la altura CD es :

5 2 5\sqrt{2} 5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

4 5 4\sqrt{5} 4 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Geometría PDT

Authored by HILDA BUSTAMANTE

Mathematics

9th Grade

Used 2+ times

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15 questions

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MULTIPLE CHOICE QUESTION

2 mins • 1 pt

La profesora de Anita le pide a ella que resuelva la siguiente operación entre vectores – (2v – 3u) , considerando los vectores v = (– 3, 1) y u = (1, – 4) en el plano cartesiano.

¿ En cuál de los pasos anteriores Anita cometió un error?

Paso 1

Paso 2

Paso 3

Paso 4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Si EF = 70 cm y FG = 40 cm, ¿cuál es la longitud del lado GE?

$\sqrt{30}$ cm

30 cm

40 cm

$10\sqrt{33}$ cm

$10\sqrt{65}$ cm

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

En la figura se ha dibujado el cuadrado PQAB de área 64 cm². Si Pr = 14 cm, ¿cuál es el perímetro (P) y cuál es el área (A) del trapecio PRAB?

P = 32 cm y A = 64 cm²

P = 32 cm y A = 88 cm²

P = 40 cm y A = 24 cm²

P = 40 cm y A = 88 cm²

P = 56 cm y A = 88 cm²

MULTIPLE CHOICE QUESTION

2 mins • 5 pts

En la figura, el cuadrado ADCB y el triangulo equilatero EBC tienen un lado común que mide 7 cm. ¿Cuál es el perimetro de la figura ADCEB?

21 cm

28 cm

35 cm

42 cm

49 cm

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Dado los vectores de la figura, si se sabe que $\overrightarrow{v\ }=\ \overrightarrow{u\ }-\ \ \overrightarrow{t\ \ }+\ \ \overrightarrow{w\ }$ ,¿ cuál es la magnitud del vector $\overrightarrow{v\ }$ ?

$\sqrt{74}$

$\sqrt{58}$

$\sqrt{53}$

$\sqrt{34}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Si en el plano cartesiano de la figura adjunta se representan 𝑣⃗ y 𝑤⃗, entonces (2𝑣⃗ - 𝑤⃗) es:

(5,9)

(3,9)

(-4,0)

(9,5)

Ninguna de los valores anteriores.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Si 𝑝 < 0, entonces la magnitud del vector (-𝑝)(𝑝², 𝑝²) es:

$\sqrt{2}p^2$

$-\ p5$

- p

$2\ p^3$

$-\ \sqrt{2}p^3$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

En la figura adjunta, el triángulo ABC es equilátero y
DB = 7 cm. El área del triángulo ACD es :

$\frac{49}{2}\sqrt{2}\ cm^2$

$\frac{49}{2}\sqrt{3}\ cm^2$

$49\sqrt{2}\ cm^2$

$49\sqrt{3}\ cm^2$

$\frac{49}{2}\ cm^2$

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Geometría PDT

La profesora de Anita le pide a ella que resuelva la siguiente operación entre vectores – (2v – 3u) , considerando los vectores v = (– 3, 1) y u = (1, – 4) en el plano cartesiano.

¿ En cuál de los pasos anteriores Anita cometió un error?

Si EF = 70 cm y FG = 40 cm, ¿cuál es la longitud del lado GE?

En la figura se ha dibujado el cuadrado PQAB de área 64 cm². Si Pr = 14 cm, ¿cuál es el perímetro (P) y cuál es el área (A) del trapecio PRAB?

En la figura, el cuadrado ADCB y el triangulo equilatero EBC tienen un lado común que mide 7 cm. ¿Cuál es el perimetro de la figura ADCEB?

Dado los vectores de la figura, si se sabe que $\overrightarrow{v\ }=\ \overrightarrow{u\ }-\ \ \overrightarrow{t\ \ }+\ \ \overrightarrow{w\ }$ ,¿ cuál es la magnitud del vector $\overrightarrow{v\ }$ ?

Si en el plano cartesiano de la figura adjunta se representan 𝑣⃗ y 𝑤⃗, entonces (2𝑣⃗ - 𝑤⃗) es:

Si 𝑝 < 0, entonces la magnitud del vector (-𝑝)(𝑝², 𝑝²) es:

En la figura adjunta, el triángulo ABC es equilátero y
DB = 7 cm. El área del triángulo ACD es :

El punto (4,1) se traslada al punto (−2,3), ¿cuál es el vector de traslación?

En la figura, △ ABC es rectángulo en C y hc
es altura. ¿Cuál(es) de las siguientes relaciones es (son) correcta(s)?

I. hc²=p⋅q
II. a²=p⋅c
III. b²=q⋅c

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Geometría PDT

La profesora de Anita le pide a ella que resuelva la siguiente operación entre vectores – (2v – 3u) , considerando los vectores v = (– 3, 1) y u = (1, – 4) en el plano cartesiano.¿ En cuál de los pasos anteriores Anita cometió un error?

Si EF = 70 cm y FG = 40 cm, ¿cuál es la longitud del lado GE?

En la figura se ha dibujado el cuadrado PQAB de área 64 cm2. Si Pr = 14 cm, ¿cuál es el perímetro (P) y cuál es el área (A) del trapecio PRAB?

En la figura, el cuadrado ADCB y el triangulo equilatero EBC tienen un lado común que mide 7 cm. ¿Cuál es el perimetro de la figura ADCEB?

Dado los vectores de la figura, si se sabe que v →= u →− t →+ w →\overrightarrow{v\ }=\ \overrightarrow{u\ }-\ \ \overrightarrow{t\ \ }+\ \ \overrightarrow{w\ }v = u − t + w ,¿ cuál es la magnitud del vector v →\overrightarrow{v\ }v ?

Si en el plano cartesiano de la figura adjunta se representan 𝑣⃗ y 𝑤⃗, entonces (2𝑣⃗ - 𝑤⃗) es:

Si 𝑝 < 0, entonces la magnitud del vector (-𝑝)(𝑝2, 𝑝2) es:

En la figura adjunta, el triángulo ABC es equilátero y DB = 7 cm. El área del triángulo ACD es :

El punto (4,1) se traslada al punto (−2,3), ¿cuál es el vector de traslación?

En la figura, △ ABC es rectángulo en C y hc es altura. ¿Cuál(es) de las siguientes relaciones es (son) correcta(s)?I. hc2=p⋅qII. a2=p⋅cIII. b2=q⋅c

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Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

La profesora de Anita le pide a ella que resuelva la siguiente operación entre vectores – (2v – 3u) , considerando los vectores v = (– 3, 1) y u = (1, – 4) en el plano cartesiano.

¿ En cuál de los pasos anteriores Anita cometió un error?

En la figura se ha dibujado el cuadrado PQAB de área 64 cm². Si Pr = 14 cm, ¿cuál es el perímetro (P) y cuál es el área (A) del trapecio PRAB?

Dado los vectores de la figura, si se sabe que $\overrightarrow{v\ }=\ \overrightarrow{u\ }-\ \ \overrightarrow{t\ \ }+\ \ \overrightarrow{w\ }$ ,¿ cuál es la magnitud del vector $\overrightarrow{v\ }$ ?

Si 𝑝 < 0, entonces la magnitud del vector (-𝑝)(𝑝², 𝑝²) es:

En la figura adjunta, el triángulo ABC es equilátero y
DB = 7 cm. El área del triángulo ACD es :

En la figura, △ ABC es rectángulo en C y hc
es altura. ¿Cuál(es) de las siguientes relaciones es (son) correcta(s)?

I. hc²=p⋅q
II. a²=p⋅c
III. b²=q⋅c