Examples Questions Yr 7 - Fr Dec %

The amount shaded (as a fraction) is:

• $\frac{3}{15}$

• $\frac{3}{12}$
  

• $\frac{3}{9}$

• $\frac{3}{10}$

What are the next three fractions in the pattern:

0,  $\frac{2}{12}$  ,  $\frac{4}{12}$  ,

•  $\frac{5}{12}$  ,  $\frac{6}{12}$  ,  $\frac{7}{12}$  

•  $\frac{6}{12}$  ,  $\frac{7}{12}$  ,  $\frac{8}{12}$  

•  $\frac{5}{12}$  ,  $\frac{7}{12\ }$  ,  $\frac{9}{12}$  

•  $\frac{6}{12}$  ,  $\frac{8}{12}$  ,  $\frac{10}{12}$  

Three equivalent fractions for $\frac{1}{3}$   would be:

•  $\frac{2}{3}$  ,  $\frac{3}{3}$  ,  $\frac{4}{3}$  

•  $\frac{2}{6}$  ,  $\frac{3}{9}$  ,  $\frac{4}{12}$  

•  $\frac{2}{6}$  ,  $\frac{3}{6}$  ,  $\frac{4}{12}$  

•  $\frac{2}{4}$  ,  $\frac{3}{5}$  ,  $\frac{4}{6}$  

 $\frac{2}{11}=\frac{12}{?}$  

The number that should be put in place of the question mark is:

• 66

• 1.83

• 33

• 21

If I FULLY simplify $\frac{12}{32}$  I will get:

•  $\frac{1}{21}$  

•  $\frac{6}{16}$  

•  $\frac{3}{8}$  

•  $\frac{6}{17}$  

The shaded parts of the diagram shows the mixed number:

•  $\frac{18}{20}$  

•  $\frac{17}{20}$  

•  $3\ \frac{2}{5}$  

•  $3\ \frac{3}{5}$  

 $3\ \frac{5}{6}$  as an improper fraction would be:

•  $\frac{23}{6}$  

•  $\frac{21}{5}$  

•  $\frac{33}{6}$  

•  $\frac{90}{6}$  

 $\frac{17}{7}$  as a mixed number is:

•  $1\ \frac{10}{7}$  

•  $2\ \frac{3}{7}$  

•  $\frac{24}{7}$  

•  $3\ \frac{4}{7}$  

 $1\ \frac{5}{6}$  ,  $2\ \frac{1}{2}$  , $1\ \frac{2}{3}$  ,  $2\ \frac{1}{6}$  , and  $1\ \frac{1}{3}$  when put in ascending order gives:

•  $1\ \frac{5}{6},\ 1\ \frac{1}{3},\ 1\ \frac{2}{3},\ 2\ \frac{1}{2},\ 2\ \frac{1}{6}$  

•  $1\ \frac{1}{3},\ 1\ \frac{2}{3},\ 1\ \frac{5}{6},\ 2\ \frac{1}{6},\ 2\ \frac{1}{2}$  

•  $1\ \frac{1}{3},\ 1\ \frac{2}{3},\ 1\ \frac{5}{6},\ 2\ \frac{1}{2},\ 2\ \frac{1}{6}$  

•   $1\ \frac{5}{6},\ 1\ \frac{2}{3},\ 1\ \frac{1}{3},\ 2\ \frac{1}{2},\ 2\ \frac{1}{6}$  

 $\frac{1}{7}\times\frac{2}{3}$  gives:

•  $\frac{3}{14}$  

•  $\frac{2}{21}$  

•  $\frac{3}{10}$  

•  $\frac{12}{73}$