Exercises 7.1 Part 2

According to the U.S. Census Bureau, the 90% confidence interval for the median household income in 2013 was $51,484 to $52,394. Interpret the confidence interval.

• We are fully confident that the interval from $51,484 to $52,394 captures the true median household income in 2013.

• We know that the interval from $51,484 to $52,394 captures the true median household income in 2013.

• We are 90% confident that the interval from $51,484 to $52,394 captures the true median household income in 2013.

• We are 90% confident that the interval from $52,394 to $51,484 captures the true median household income in 2013.

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CCSS.HSS.IC.B.4

Tim purchased a random sample of clementines at a local grocery store. The 95% confidence interval for the mean weight of all clementines at this store is 76.6 grams to 90.1 grams. Interpret this confidence interval.

• We are 95% confident that the interval from 76.6 grams to 90.1 grams captures the true mean weight of all clementines at this store.

• We are 95% confident that the interval from 90.1 grams to 76.6 grams captures the true mean weight of all clementines at this store.

• We are confident that the interval from 76.6 grams to 90.1 grams captures all the mean weights of all clementines at this store.

• We are fully confident that the interval from 76.6 grams to 90.1 grams captures the true mean weight if all clementines at this store.

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CCSS.HSS.IC.B.4

According to the U.S. Census Bureau, the 90% confidence interval for the median household income in 2013 was $51,484 to $52,394. Calculate the point estimate of the confidence interval.

• $51,484

• $51,939

• $52,394

• $52,000

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CCSS.HSS.IC.B.4

According to the U.S. Census Bureau, the 90% confidence interval for the median household income in 2013 was $51,484 to $52,394. Calculate the margin of error for the confidence interval.

• $910

• $555

• $810

• $455

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CCSS.HSS.IC.B.4

Tim purchased a random sample of clementines at a local grocery store. The 95% confidence interval for the mean weight of all clementines at this store is 76.6 grams to 90.1 grams. Calculate the point estimate of this confidence interval.

• 83.35 grams

• 76.6 grams

• 90.1 grams

• 85.35 grams

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CCSS.HSS.IC.B.4

Tim purchased a random sample of clementines at a local grocery store. The 95% confidence interval for the mean weight of all clementines at this store is 76.6 grams to 90.1 grams. Calculate the margin of error of this confidence interval.

• 13.5 grams

• 12.5 grams

• 6.75 grams

• 5.75 grams

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CCSS.HSS.IC.B.4

According to the U.S. Census Bureau, the 90% confidence interval for the median household income in 2013 was $51,484 to $52,394.

Suppose that $51,759 was the median income for all households in 2012. Does the interval provide convincing evidence that the median household income increased in 2013?

• Yes, since $51,759 is in the interval.

• No, since $51,759 is in the interval.

• Yes, since $51,759 is not in the interval.

• No, since $51,759 is not in the interval.

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CCSS.HSS.IC.B.4

Tim purchased a random sample of clementines at a local grocery store. The 95% confidence interval for the mean weight of all clementines at this store is 76.6 grams to 90.1 grams.

The nutritional label on a bag of clementines says a they typically weigh 74 grams each. Does the interval provide convincing evidence that the mean weight of clementines from this store is larger than the nutritional label suggests?

• No, since 74 grams falls in the interval.

• No, since 74 grams does not fall in the interval.

• Yes, since 74 grams falls in the interval.

• Yes, since 74 grams does not fall in the interval.

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CCSS.HSS.IC.B.4