Solving Quadratic Functions by Factoring

You are given the factored equation  $\left(x+8\right)\left(x-2\right)=0$  . What is the next step to solve for x.

• Set  $x+8=0$  and $x-2=0$  

• Nothing the solution is  $x=8$  and  $x=-2$  

• Multiply  $\left(x+8\right)\left(x-2\right)$  

• Choose  $x+8$  or  $x-2$  and write a musical about them

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.4

Solve  $\left(x+2\right)\left(x-11\right)=0$  for x.

•  $x=-2$  or  $x=-11$  

•  $x=2$  or  $x=-11$  

•  $x=2$  or  $x=11$  

•  $x=-2$  or  $x=11$  

Tags

CCSS.HSA.REI.B.4

Solve  $\left(3x-7\right)\left(2x-8\right)=0$  for x

•  $x=-\frac{7}{3}$  or  $x=4$  

•  $x=-\frac{7}{3}$  or  $x=-4$  

•  $x=\frac{7}{3}$  or  $x=4$  

•  $x=\frac{7}{3}$  or  $x=-4$  

Tags

CCSS.HSA.REI.B.4

Solve by factoring:  $x^2-9x+20=0$  What does the factoring step look like?

•  $\left(x-4\right)\left(x+5\right)=0$  

•  $\left(x+20\right)\left(x-9\right)=0$  

•  $\left(x-4\right)\left(x-5\right)=0$  

•  $\left(x+4\right)\left(x+5\right)=0$  

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Solve by factoring:  $x^2-9x+20=0$  

• x = - 4 and x = - 5

• x = 20 and x = - 9

• x = 4 and x = 5

• x = - 4 and x = 5

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

Solve by factoring 
 $x^2+12x+35=0$  

• x = - 5 or x = - 7

• x = 5 or x = 7

• x = - 35 or x = - 1

• x = - 9 or x = - 4

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Find two numbers which add to make 6 and multiply to make -13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

Solve using Zero-Product Property:
 $(2x-2)(5x+5)=0$  

• x = -1

• x = -1 or x = 1

• x = 1

• x = -2 or x = 5

Tags

CCSS.HSA.REI.B.4

What is the factored form of  $4x^2+4x+1=0$  ?

•  $\left(2x+1\right)\left(2x+1\right)=0$  

•  $\left(2x-1\right)\left(2x+1\right)$  

•  $\left(2x-1\right)\left(2x-1\right)$  

•  $\left(4x+1\right)\left(1x+1\right)$  

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

What is the solution for  $4x^2+4x+1=0$  ?

•  $x=\frac{1}{2}or\ x=-\frac{1}{2}$  

•  $x=-\frac{1}{2}and\ x=-\frac{1}{2}$  

•  $x=\frac{1}{2\ }and\ x=\frac{1}{2}$  

•  $x=\frac{1}{4}or\ x=1$  

Tags

CCSS.HSA.REI.B.4