Persamaan Lingkaran

Persamaan Lingkaran

11th Grade

10 Qs

quiz-placeholder

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Persamaan Lingkaran

Persamaan Lingkaran

Assessment

Quiz

Mathematics

11th Grade

Medium

Created by

Siti Hanifah

Used 98+ times

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Persamaan lingkaran yang berpusat di (0,0) dan berjari-jari 2 3\sqrt{3}  

 x2+y2=12x^2+y^2=12  

 x2+y2=10x^2+y^2=10  

 x2+y2=8x^2+y^2=8  

 x2+y2=6x^2+y^2=6  

 x2+y2=4x^2+y^2=4  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Persamaan lingkaran berpusat di (-2,3) berjari-jari 4 adalah ....

(x2)2+(y+3)2=4\left(x-2\right)^2+\left(y+3\right)^2=4

(x+2)2+(y3)2=4\left(x+2\right)^2+\left(y-3\right)^2=4

(x2)2+(y+3)2=16\left(x-2\right)^2+\left(y+3\right)^2=16

(x+2)2+(y3)2=16\left(x+2\right)^2+\left(y-3\right)^2=16

(x+2)2+(y3)2=36\left(x+2\right)^2+\left(y-3\right)^2=36

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Persamaan lingkaran yang berpusat di titik P(-2,7) dan menyinggung sumbu X adalah ....

(x2)2+(y+7)2=49\left(x-2\right)^2+\left(y+7\right)^2=49

(x+2)2+(y7)2=49\left(x+2\right)^2+\left(y-7\right)^2=49

(x2)2+(y+7)2=36\left(x-2\right)^2+\left(y+7\right)^2=36

(x+2)2+(y7)2=4\left(x+2\right)^2+\left(y-7\right)^2=4

(x2)2+(y+7)2=4\left(x-2\right)^2+\left(y+7\right)^2=4

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Pusat dan jari-jari lingkaran yang persamaannya  (x+6)2+(y5)2=64\left(x+6\right)^2+\left(y-5\right)^2=64  adalah ....

Pusat (-5,6) dan jari-jari 8

Pusat (6,-5) dan jari-jari 64

Pusat (6,-5) dan jari-jari 8

Pusat (-6,5) dan jari-jari 64

Pusat (-6,5) dan jari-jari 8

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Persamaan lingkaran yang berpusat di titik O(0,0) dan melalui titik (2,-3)

x2+y2=13x^2+y^2=13

x2+y2=16x^2+y^2=16

x2+y2=25x^2+y^2=25

x2y2=13x^2-y^2=13

x2y2=16x^2-y^2=16

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Persamaan lingkaran yang berpusat di (-1,2) dan melalui titik (3,4) adalah ....

(x1)2+(y+2)2=20\left(x-1\right)^2+\left(y+2\right)^2=20

(x1)2+(y+2)2=20\left(x-1\right)^2+\left(y+2\right)^2=\sqrt{20}

(x+1)2+(y2)2=20\left(x+1\right)^2+\left(y-2\right)^2=20

(x+1)2+(y2)2=20\left(x+1\right)^2+\left(y-2\right)^2=\sqrt{20}

(x+1)2+(y2)2=25\left(x+1\right)^2+\left(y-2\right)^2=25

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Soal UN 2013
Persamaan lingkaran yang berpusat pada titik  (4,3)\left(4,-3\right)  dan berdiameter 8  adalah....

 x2+y28x+6y=0x^2+y^2-8x+6y=0  

 x2+y2+8x6y+16=0x^2+y^2+8x-6y+16=0  

 x2+y28x+6y+16=0x^2+y^2-8x+6y+16=0  

 x2+y2+8x6y+9=0x^2+y^2+8x-6y+9=0  

 x2+y28x+6y+9=0x^2+y^2-8x+6y+9=0  

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