Right Triangle Trigonometry

Right Triangle Trigonometry

9th - 12th Grade

14 Qs

quiz-placeholder

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Right Triangle Trigonometry

Right Triangle Trigonometry

Assessment

Quiz

Mathematics

9th - 12th Grade

Hard

CCSS
HSG.SRT.C.8, HSG.SRT.C.6, HSF.TF.C.8

+3

Standards-aligned

Created by

Joseph Krontz

Used 49+ times

FREE Resource

14 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

Media Image

Which of the following trigonometric ratios are correct for the right triangle?

(Select ALL that apply)

sinA=2425\sin A=\frac{24}{25}

cosA= 725\cos A=\ \frac{7}{25}

sinC=725\sin C=\frac{7}{25}

tanC=724\tan C=\frac{7}{24}

cosC=2524\cos C=\frac{25}{24}

Tags

CCSS.HSF.TF.C.8

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

If  cosθ=1213\cos\theta=\frac{12}{13}   , then  \sin\theta=?  

 135\frac{13}{5}  

 513\frac{5}{13}  

 512\frac{5}{12}  

 125\frac{12}{5}  

 1213\frac{12}{13}  

Tags

CCSS.HSF.TF.C.8

CCSS.HSG.SRT.C.8

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

If  sinθ=35\sin\theta=\frac{3}{5}   , then  tanθ=?\tan\theta=?  

 35\frac{3}{5}  

 53\frac{5}{3}  

 43\frac{4}{3}  

 34\frac{3}{4}  

 45\frac{4}{5}  

Tags

CCSS.HSF.TF.C.8

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

Which trigonometric ratio would you use to solve for x?

Sine

Cosine

Tangent

None

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

Which trigonometric ratio would you use to solve for x?

Sine

Cosine

Tangent

None

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

Which trigonometric ratio would you use to solve for x?

Sine

Cosine

Tangent

None

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Which trigonometric equation would correctly solve for x?

sin(37)=x23\sin\left(37\right)=\frac{x}{23}

sin(37)=23x\sin\left(37\right)=\frac{23}{x}

cos(37)=x23\cos\left(37\right)=\frac{x}{23}

cos(37)=23x\cos\left(37\right)=\frac{23}{x}

tan(37)=x23\tan\left(37\right)=\frac{x}{23}

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

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