2.2 Review #3

This block of mass m is in translational equilibrium.

There is friction on the plane-block.

Choose the correct equation parallel to the plane.

• Wsinø - Ff = 0

• Wsinø + Ff = 0

• Wsinø + Ff = ma

• Wsinø - Ff = ma

This block of mass m is in translational equilibrium.

There is friction on the plane-block.

Normal force = ....

• Wcosø

• Wsinø

• Wcosø - F

• Wsinø - F

This block of mass m is in translational equilibrium.

There is friction on the plane-block.

Block is sliding down with ....

• constant velocity

• constant acceleration

• increasing velocity

• increasing acceleration

This block of mass m is in translational equilibrium.

There is friction on the plane-block.

Block is sliding down. Choose the correct option.

• Wsinø - μd•Wcosø = 0

• Wsinø - μd•Wsinø = 0

• Wcosø - μd•Wcosø = 0

• Wcosø - μd•Wsinø = 0

This block of mass m.

There is friction on the plane-block.

Block is sliding down with acceleration. Choose correct option.

• Wsinø - μd•Wcosø = m•a

• Wsinø - μd•Wsinø = m•a

• Wcosø - μd•Wcosø = W•a

• Wcosø - μd•Wsinø = W•a

This block of mass m.

There is friction on the plane-block.

Block is sliding down with acceleration. Choose the correct option.

• Wsinø > μd•Wcosø

• Wsinø < μd•Wsinø

• Wcosø > μd•Wcosø

• Wcosø < μd•Wsinø

This block of mass m is not moving.

There is friction on the plane-block.

Choose the correct option.

• Wsinø ≥ μs•Wcosø

• Wsinø ≤ μs•Wcosø

• Wcosø ≤ μs•Wcosø

• Wcosø ≥ μs•Wsinø

What are the forces on y-axis with this block mass m?

• R + F•sinø – mg = 0

• R + F•sinø – mg = ma

• R + F•scosø – mg = 0

• R + F•cosø – mg = ma

Object not moving, there is an applied force F. (neglect v)

What are the forces on the x-axis with this block mass m?

• μs•(mg - F•sinø) - F•cosø = 0

• μs•mg - F•sinø = 0

• μs•(mg - F•cosø) - F•sinø = 0

• μs•mg - F•cosø = 0

Object is moving, there is an applied force F with acceleration.

What are the forces on the x-axis with this block mass m?

• μd•(mg - F•sinø) – F•cosø = ma

• μd•mg - F•sinø = ma

• μs•(mg - F•cosø) – F•sinø = ma

• μs•mg - F•cosø = ma