CONIC SECTION - HYPERBOLA

Determine the length of the transverse axis

• 1.5

• 2

• 3

• 4

Tags

CCSS.HSG.GPE.A.3

Determine the equation of the hyperbola.

• $\frac{x^2}{4}-y^2=1$

• $\frac{x^2}{2}-y^2=1$

• $\frac{x^2}{4}+y^2=1$

• $\frac{x^2}{2}+y^2=1$

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GPE.A.3

What is the equation describing the relationship between dimensions and foci of a hyperbola?

• c² = a² + b²
• c² = a² - b²
• 4p
• (x-h)² + (y-k)² = r²

Tags

CCSS.HSG.GPE.A.3

Is the hyperbola vertical or horizontal? 

• Vertical
• Horizontal

Tags

CCSS.HSG.GPE.A.3

Coordinates of the foci of the hyperbola

 $\frac{x^2}{9}-\frac{y^2}{16}=1$  are

•  $\left(\pm\ 3,\ 0\right)$  

•  $\left(\pm\ 4,\ 0\right)$  

•  $\left(\pm\ 5,\ 0\right)$  

• none of these

Equation of the hyperbola with vertices

 $\left(0,\ \pm\ 5\right)$  and foci  $\left(0,\ \pm\ 8\right)$  is

•  $\frac{y^2}{25}-\frac{x^2}{39}=1$  

•  $\frac{x^2}{25}-\frac{y^2}{39}=1$  

•  $\frac{x^2}{25}+\frac{y^2}{39}=1$  

• none of these

Equation of hyperbola if length of transverse axis is 8 and foci $\left(\pm\ 5,\ 0\right)$  

•  $\frac{x^2}{16}-\frac{y^2}{9}=1$  

•  $\frac{x^2}{9}-\frac{y^2}{16}=1$  

•  $\frac{y^2}{16}-\frac{x^2}{9}=1$  

• none of these