Tangents and Normals

Tangents and Normals

12th Grade - University

8 Qs

quiz-placeholder

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Tangents and Normals

Tangents and Normals

Assessment

Quiz

Mathematics

12th Grade - University

Medium

Created by

Nilesh gulati

Used 87+ times

FREE Resource

8 questions

Show all answers

1.

FILL IN THE BLANK QUESTION

45 sec • 1 pt

The slope of the tangent to curve  y=x3  x+1y=x^3\ –\ x+1 at the point whose x - coordinate is 2 is 

2.

FILL IN THE BLANK QUESTION

1 min • 1 pt

The slope of the normal to the curve x=acos3θ,  y=asin3θx=a\cos^3\theta,\ \ y=a\sin^3\theta at  θ=π4\theta=\frac{\pi}{4}  is 

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The equation of the tangent line to the curve y = x2 – 2x +7 which is parallel to the line 2x – y + 9 = 0 is

y 2x 3=0y\ –\ 2x\ –\ 3=0

y +2x 3=0y\ +2x\ –\ 3=0

y 2x + 3=0y\ –\ 2x\ +\ 3=0

y +2x + 3=0y\ +2x\ +\ 3=0

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The equation of normal to the curve y = tan x at (0, 0) is ________

xy=0x-y=0

x+y=1x+y=1

x+y=0x+y=0

xy=1x-y=1

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The point on the curve  y2=xy^2=x , where the tangent makes an angle of  \frac{\pi}{4}  with x-axis is

 (12,14)\left(\frac{1}{2},\frac{1}{4}\right)  

 (14,12)\left(\frac{1}{4},\frac{1}{2}\right)  

 (4, 2)\left(4,\ 2\right)  

 (1, 1)\left(1,\ 1\right)  

6.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

More than one correct: The points on the curve y=x^3  at which the slope of the tangent is equal to the y - coordinate of the point are

 (0, 0)\left(0,\ 0\right)  

 (2, 8)\left(2,\ 8\right)  

 (1, 1)\left(1,\ 1\right)  

 (3, 27)\left(3,\ 27\right)  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The equation of the normal to the curve y=x^4–\ 6x^3+13x^2\ –\ 10x+5  at  (0, 5)\left(0,\ 5\right)  is

 x  +10y+50=0x\ \ +10y+50=0  

 x  10y+50=0x\ –\ 10y+50=0  

 x  10y50=0x\ –\ 10y-50=0  

 x +10y+50=0x\ +10y+50=0  

8.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The equations of all lines having slope 0 which are tangent to the curve y=\frac{1}{x^2-2x+3}  is

 y=1y=1  

 2y=12y=1  

 2y+1=02y+1=0  

 y+1=0y+1=0