Fractions - Multiplication and Division

Simplify to the lowest or simplest terms $\frac{12}{18}$  

•  $\frac{6}{9}$  

•  $\frac{4}{3}$  

•  $\frac{2}{3}$  

•  $\frac{3}{6}$  

Tags

CCSS.4.NF.A.1

Simplify to the lowest or simplest terms  $\frac{21}{72}$  

• You can't simplify

•  $\frac{7}{9}$  

•  $\frac{3}{8}$  

•  $\frac{7}{24}$  

Tags

CCSS.6.NS.B.4

Simplify to the lowest or simplest terms  $\frac{32}{48}$  

•  $\frac{8}{12}$  

•  $\frac{6}{8}$  

•  $\frac{2}{3}$  

•  $\frac{4}{6}$  

Tags

CCSS.4.NF.A.1

CCSS.4.OA.B.4

 $2\ \frac{1}{3}\div\frac{32}{48}$  = 

•  $3\ \frac{5}{6}$  

•  $\frac{23}{6}$  

•  $3\ \frac{1}{2}$   

•  $\frac{21}{9}$  

Tags

CCSS.5.NF.B.3

Find the product of  $\frac{1}{7}$ X  $\frac{5}{7}$  *Remember  $\frac{3}{5}$ = 3/5

Tags

CCSS.5.NF.B.4

CCSS.5.NF.B.5

CCSS.5.NF.B.6

To find the product I can rewrite the expression as:

•  $\frac{1}{5}$  X  $\frac{3}{7}$  

•  $\frac{5}{1}$  X  $\frac{3}{7}$  

•  $\frac{5}{5}$  X  $\frac{3}{7}$  

Tags

CCSS.5.NF.B.4

CCSS.5.NF.B.5

To find the product...

• Numerator = (1x7). Denominator = (5x3)

• Numerator = (5x7). Denominator = (1x3)

• Numerator = (5x3). Denominator = (1+7)

• Numerator = (5x3). Denominator = (1x7)

Tags

CCSS.5.NF.B.4

The last step is...

• 7 $\div$ 15 = 2 $\frac{1}{7}$

• 15 $\div$ 7 = 2 $\frac{2}{7}$

• 15 $\div$ 7 = 2 $\frac{1}{7}$

• 7 $\div$ 15 = 2 $\frac{2}{7}$

Tags

CCSS.5.NF.B.3

To find the quotient the next step is...

•  $\frac{3}{4}\div\frac{2}{3}$  

•  $\frac{12}{3}\div\frac{2}{2}$  

•  $\frac{14}{3}\div\frac{3}{2}$  

•  $\frac{15}{3}\div\frac{3}{2}$  

Tags

CCSS.5.NF.B.3

CCSS.5.NF.B.7

To find the quotient the next step is...

• KEEP the 2nd fraction, FLIP the 1st, and CROSS to multiply.

• KEEP the 2nd fraction, FLIP the 1st, and CROSS to divide.

• KEEP the 1st fraction, FLIP the 2nd, and CROSS to multiply.

• KEEP the 1st fraction, FLIP the 2nd, and CROSS to divide.

Tags

CCSS.5.NF.B.3

CCSS.5.NF.B.7