Ambiguous Case: Law of Sine

Ambiguous Case: Law of Sine

10th - 12th Grade

10 Qs

quiz-placeholder

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Ambiguous Case: Law of Sine

Ambiguous Case: Law of Sine

Assessment

Quiz

Mathematics, Other

10th - 12th Grade

Medium

CCSS
HSG.SRT.D.10, HSG.SRT.D.11

Standards-aligned

Created by

Jaclyn Dragon

Used 339+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

State the number of possible triangles that can be formed using the given measurements.
 B=139°, a=12 cm, b=35 cmB=139\degree,\ a=12\ cm,\ b=35\ cm  

Two Triangles

One Triangle

None

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

State the number of possible triangles that can be formed using the given measurements.
 B=147°, a=25 km, b=15 kmB=147\degree,\ a=25\ km,\ b=15\ km  

Two Triangles

One Triangle

None

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

State the number of possible triangles that can be formed using the given measurements.
 A=36°, c=30 km, a=26 kmA=36\degree,\ c=30\ km,\ a=26\ km  

Two Triangles

One Triangle

None

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

What is the measure of angle A?

58°58\degree and 122°122\degree

61°61\degree and 119°119\degree

78°78\degree and 102°102\degree

74°74\degree and 106°106\degree

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the indicated angle.

49°49\degree

29°29\degree

49°49\degree and 131°131\degree

29°29\degree and 151°151\degree

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve the Triangle(s):  a=14a=14 ,  b=6b=6 , A=27°A=27\degree  

no triangle possible

B = 11.219o, C = 141.781o, c = 19.078

B = 38.219o, C = 114.781o, c = 27.998

B = 11.219o, C = 141.781o, c = 19.078

OR

B = 38.219o, C = 114.781o, c = 27.998

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve the Triangle(s): A = 26o, a = 5, b = 9

no triangle possible

B = 14o, C = 21o, c = 8.7

B = 52o, C = 102o, c = 11.2

B = 52o , C = 102o, c = 11.2

OR

B = 128o, C = 26o, c = 5.0

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

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