Newton's Second Law Review

One kg multiplied by m/s² can also be expressed as 1 __________.

• direction
• mass
• kilogram²
• newton

Tags

NGSS.HS-PS2-1

Calculate the Acceleration.

• 20 m/s/s

• 5 m/s/s

• .2 m/s/s

• 80 m/s/s

Tags

NGSS.HS-PS2-1

What are the net force equations for this car?

• In x: 1000 + 300 = 1300N; In y: 500 + 500 = 1000N

• In x: 1000 - 300 = 700N; In y: 500 + 500 = 1000N

• In x: 1000 + 300 = 1300N; In y: 500 - 500 = 0N

• In x: 1000 - 300 = 700N; In y: 500 - 500 = 0N

Tags

NGSS.HS-PS2-1

Which equation would accurately describe the forces on this cup of coffee?

• $F_n\ +\ F_g\ =\ 0$

• $F_n\times F_g\ =\ 0$

• $F_n-10F_g$

• $F_n-F_g\ =\ -10$

Tags

NGSS.HS-PS2-1

A rightward force of 302 N is applied to a 28.6 kg crate to accelerate it across the floor. The

coefficient of friction between the crate and the floor is 0.750. Determine the acceleration of the crate. (Take g = 9.81m/s/s)

• 9.81m/s/s

• 7.94m/s/s

• 3.20m/s/s

• 91.6m/s/s

Tags

NGSS.HS-PS2-1

If a force of 26 N is exerted on two balls, one with a mass of 0.52 kg and the other with a mass of 0.78 kg, which ball will have the greater acceleration?

• The one with a mass of .78 kg will have the greatest acceleration.

• The one with a mass of .52 kg will have the greatest acceleration.

• They will both accelerate at the same rate.

Tags

NGSS.HS-PS2-1

The mass of a large car is 1000 kg.  The car accelerates at a rate of 3 m/sec²? If the car’s engine generates a 2800 N force forward, calculate the force of friction.

• - 200 N
• - 2800 N
• - 5.8 N
• 8.4 N

Tags

NGSS.HS-PS2-1

A 6.58 x 103 N upward tension force is exerted on a 521kg downward moving freight elevator.

Determine the acceleration of the elevator.

(Take g = 9.81m/s/s)

• 2.82m/s/s^ upwards

• 2.82m/s/s^ downwards

• 12.6m/s/s upwards

• 12.6m/s/s downwards

• Not enough information in the question

Tags

NGSS.HS-PS2-1

An elevator accelerates at -2.0 m/s², as illustrated in the diagram below:
The passenger has a mass of 85 kg.  Calculate the force the floor exerts on the passenger.

• 1003 N
• 0 N
• 833 N
• 663 N

Tags

NGSS.HS-PS2-1

A basketball star exerts a force of 3225 N (average value) upon the gym floor in order to accelerate his 76.5 kg body upward.

Determine the acceleration of the player.

(Take g = 9.81m/s/s)

• Not enough force to overcome gravity

• 42.2m/s/s

• 32.2m/s

• 32.3m/s/s

Tags

NGSS.HS-PS2-1