Circle Systems

Determine the equation of a circle with center (5,-3) and radius of 9

• x²+y²-10x+6y-47=4
• x²+y²-10x-6y-47=0
• 2x²+y²+10x+6y-47=0
• x²+y²-10x+6y-47=0

Tags

CCSS.HSG.GPE.A.1

Write the equation of the circle in general form.

• A

• B

• C

• D

Tags

CCSS.HSG.GPE.A.1

Which of the following equations of circle in general form given the center at (3, 4) and radius of 5 units?

• (x – 3)² - (y – 4)² = 25

• (x – 3)² + (y – 4)² = 25

• x² + y² + 6x - 8y - 25 = 0

• x² + y² - 6x - 8y = 0

Tags

CCSS.HSG.GPE.A.1

Which of the following equations of circle in general form given the center at (5, -8) and radius of 11 units?

• x² + y² -10x + 16y + 32 = 0

• x² + y² -10x + 16y - 32 = 0

• (x - 5)² + (y + 8)² = 11

• (x - 5)² + (y + 8)² = 121

Tags

CCSS.HSG.GPE.A.1

How can we find the general form of a circle? 

• divide out the center-radius form
• multiply out the center-radius form
• factor out the center-radius form
• add up the center-radius form

Tags

CCSS.HSG.GPE.A.1

Determine the equation of a circle with center (5,-3) and radius of 9

• x²+y²-10x+6y-47=4
• x²+y²-10x-6y-47=0
• 2x²+y²+10x+6y-47=0
• x²+y²-10x+6y-47=0

Tags

CCSS.HSG.GPE.A.1

What are the solution(s) to the system of equations? (use graph paper)

 $x^2+\left(y-2\right)^2=16$  

 $y-x=6$  

• (0, -6)  (4, -2)

• (0, 6)  (4, 2)

• (-4, 2)  (0, 6)

• no solution

What are the solution(s) to the system of equations? (use graph paper)

 $\left(x+4\right)^2+\left(y-1\right)^2=25$  
 $x=1$  

• (1, 1)

• (-9, 1)  (1, 1)

• (-4, 6)

• (-4, 6)  (-4, -4)

Convert from standard to general form: $\left(x+6\right)^2+\left(y-2\right)^2=5$  

•  $x^2+y^2=25$  

•  $x^2+y^2+12x-4y+35=0$  

•  $x^2+y^2-12x+4y+35=0$  

•  $x^2+y^2+6x-2y+35=0$  

Convert from standard to general form: $\left(x-2\right)^2+\left(y+4\right)^2=13$  

•  $x^2+y^2-4x+8y+7=0$  

•  $x^2+y^2-2x+4y+7=0$  

•  $x^2+y^2+4x-8y+7=0$  

•  $x^2+y^2+2x-4y+7=0$