Using Logs Assessment

I can write logarithmic equations in exponential form.

• A
• B
• C
• D

Tags

CCSS.HSF.BF.B.5

I can write logarithmic equations in exponential form.

• A
• B
• C
• D

Tags

CCSS.HSF.BF.B.5

Rewrite as an exponential: log₂8 = 3

• 3² = 8

• 2³ = 8

• 2⁸ = 3

• 8³ = 2

Tags

CCSS.HSF.BF.B.5

Rewrite as an exponential:  $\log_7\left(\frac{1}{49}\right)=-2$  

•  $7^{\frac{1}{49}}=-2$  

•  $\left(\frac{1}{49}\right)^{-2}=7$  

•  $7^{-2}=\frac{1}{49}$  

•  $\left(-2\right)^7=\frac{1}{49}$  

Tags

CCSS.HSF.BF.B.5

Rewrite as an exponential:  $\log_93=\frac{1}{2}$  

•  $9^{\frac{1}{2}}=3$  

•  $3^{\frac{1}{2}}=9$  

•  $9^3=\frac{1}{2}$  

•  $\left(\frac{1}{2}\right)^9=3$  

Tags

CCSS.HSF.BF.B.5

Find x: log₂(32) = x

• x = 5

• x = 16

• x = 4

• x = 6

Tags

CCSS.HSF.BF.B.5

Find x: log₅(x) = 4

• x = 20

• x = 25

• x = 625

• x = 125

Tags

CCSS.HSF.BF.B.5

Find x: log_x(25) = 2

• x = 1

• x = 12.5

• No Solution

• x = 5

Tags

CCSS.HSF.BF.B.5

Find x:  $\log_7\left(\frac{1}{7}\right)=x$  

• x = -1

• x = 1

• x = 0

• No Solution

Tags

CCSS.HSF.BF.B.5

Find x: log₅(x) = 0

• No Solution

• x = 0

• x = 5

• x = 1

Tags

CCSS.HSF.BF.B.5