Invers Logaritma Natural

Invers Logaritma Natural

University

10 Qs

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Invers Logaritma Natural

Invers Logaritma Natural

Assessment

Quiz

Mathematics

University

Practice Problem

Medium

Created by

Yessi Affri

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10 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Fungsi f merupakan fungsi injektif jika  x1x2x_1\ne x_2  sedemikian hingga...

 f(x1)f(x2)f\left(x_1\right)\ne f\left(x_2\right)  

 f(x1)=f(x2)f\left(x_1\right)=f\left(x_2\right)  

 f(x1)f(x2)f\left(x_1\right)\ge f\left(x_2\right)  

 f(x1)f(x2)f\left(x_1\right)\le f\left(x_2\right)  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Fungsi injeksi f memiliki invers  f1f^{-1}   yang memenuhi  f1(f(x))=f^{-1}\left(f\left(x\right)\right)=  _____

 f(x)f\left(x\right)  

y

x

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Fungsi injeksi f memiliki invers  f1f^{-1}  yang memenuhi  f(......)f\left(......\right) = y

 f1(y)f^{-1}\left(y\right)  

y

x

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Kriteria berguna untuk f yang injektif (dengan demikian juga memiliki invers) pada suatu domain adalah f harus _____ yang bermakna bahwa f _____ atau _____.

Beragam; Naik; Turun

Beragam; Terbuka; Tertutup

Monoton; Naik; Turun

Monoton; Terbuka; Tertutup

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Jika  y=f(x)y=f\left(x\right)  , dimana f memiliki invers  f1f^{-1}  . Persamaan yang menghubungkan f dan  f1f^{-1}   adalah...

 (f1)(y)=f(x)\left(f^{-1}\right)'\left(y\right)=f'\left(x\right)  

 (f1)(y)=1f(x)\left(f^{-1}\right)'\left(y\right)=\frac{1}{f'\left(x\right)}  

 (f1)(y)=f1(x)\left(f^{-1}\right)'\left(y\right)=f^{-1}\left(x\right)  

 (f1)(y)=1f1(x)\left(f^{-1}\right)'\left(y\right)=\frac{1}{f^{-1}\left(x\right)}  

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Fungsi ln _____ pada  \left(0,\infty\right) sehingga memiliki invers yang dapat dituliskan sebagai  ln1\ln^{-1}  atau _____

Naik;  1ln\frac{1}{\ln}  

Naik; exp

Turun;  1ln\frac{1}{\ln}  

Turun; exp

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Bilangan e terdefinisi dalam ln sebagai _____

lne=e\ln e=e

lne=2,72\ln e=2,72

lne=1\ln e=1

lne=1e\ln e=\frac{1}{e}

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