Unit 18 - Vectors and Geometric Proof

Unit 18 - Vectors and Geometric Proof

9th - 12th Grade

10 Qs

quiz-placeholder

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Unit 18 - Vectors and Geometric Proof

Unit 18 - Vectors and Geometric Proof

Assessment

Quiz

Mathematics

9th - 12th Grade

Practice Problem

Medium

CCSS
HSN.VM.A.2, HSN-VM.B.4A, HSN.CN.B.6

+3

Standards-aligned

Created by

Yousuf Patel

Used 13+ times

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

(3 4) and (5 8)\left(3\ 4\right)\ and\ \left(-5\ 8\right)

(3 4) and (5 8)\left(3\ 4\right)\ and\ \left(5\ -8\right)

(3 4) and (6 8)\left(3\ 4\right)\ and\ \left(-6\ 8\right)

(5 4) and (6 8)\left(5\ 4\right)\ and\ \left(6\ 8\right)

Tags

CCSS.HSN-VM.B.4A

CCSS.HSN-VM.B.4B

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

(4 2)\left(4\ \ 2\right)

(4 2)\left(4\ -2\right)

(2 1)\left(2\ -1\right)

(2 1)\left(-2\ 1\right)

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

MB=12a and MN=12a+12c\overrightarrow{MB}=\frac{1}{2}a\ and\ \overrightarrow{MN}=\frac{1}{2}a+\frac{1}{2}c

MB=12a and MN=12a12c\overrightarrow{MB}=\frac{1}{2}a\ and\ \overrightarrow{MN}=-\frac{1}{2}a-\frac{1}{2}c

MB=12a and MN=12a12c\overrightarrow{MB}=-\frac{1}{2}a\ and\ \overrightarrow{MN}=\frac{1}{2}a-\frac{1}{2}c

MB=12a and MN=12a12c\overrightarrow{MB}=\frac{1}{2}a\ and\ \overrightarrow{MN}=\frac{1}{2}a-\frac{1}{2}c

Tags

CCSS.HSN.CN.B.6

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

29\sqrt{29}

21\sqrt{21}

29\sqrt{-29}

5.45.4

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

a+b, 2(a+b),3a+3ba+b,\ 2\left(a+b\right),3a+3b

a+b, 2(a+b),3a+3b, 2a+2ba+b,\ 2\left(a+b\right),3a+3b,\ 2a+2b

a+b,3a+3b, 2a+2ba+b,3a+3b,\ 2a+2b

2(a+b),3a+3b, 2a+2b2\left(a+b\right),3a+3b,\ 2a+2b

6.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

Media Image

Write the vector  \overrightarrow{SR}   in terms of a and b

b-a

-b + a

a + b

-a + b

Tags

CCSS.HSN-VM.B.4C

7.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

Media Image

 T is 13along the vector RS, write the vector RT in terms of a and bT\ is\ \frac{1}{3}along\ the\ vector\ \overrightarrow{RS},\ write\ the\ vector\ \overrightarrow{RT}\ in\ terms\ of\ a\ and\ b  

Write your question here

 13(b+a)\frac{1}{3}\left(-b+a\right)  

 13(ab)\frac{1}{3}\left(a-b\right)  

 23(b+a)\frac{2}{3}\left(-b+a\right)  

 23(a+b)\frac{2}{3}\left(-a+b\right)  

Tags

CCSS.HSN.VM.A.3

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