sin ⁡ ( α + β ) = \sin\left(\alpha+\beta\right)= sin ( α + β ) =

sin ⁡ α cos ⁡ β + sin ⁡ β cos ⁡ α \sin\alpha\ \cos\beta+\sin\beta\ \cos\alpha sin α cos β + sin β cos α

sin ⁡ α cos ⁡ β − sin ⁡ β cos ⁡ α \sin\alpha\ \cos\beta-\sin\beta\ \cos\alpha sin α cos β − sin β cos α

cos ⁡ α c o β + sin ⁡ α sin ⁡ β \cos\alpha\ co\beta\ +\sin\alpha\ \sin\ \beta cos α c o β + sin α sin β

cos ⁡ α c o β − sin ⁡ α sin ⁡ β \cos\alpha\ co\beta\ -\sin\alpha\ \sin\ \beta cos α c o β − sin α sin β

sin ⁡ ( α − β ) = \sin\left(\alpha-\beta\right)= sin ( α − β ) =

sin ⁡ α cos ⁡ β − sin ⁡ β cos ⁡ α \sin\alpha\ \cos\beta-\sin\beta\ \cos\alpha sin α cos β − sin β cos α

sin ⁡ α cos ⁡ β + sin ⁡ β cos ⁡ α \sin\alpha\ \cos\beta+\sin\beta\ \cos\alpha sin α cos β + sin β cos α

cos ⁡ α c o β + sin ⁡ α sin ⁡ β \cos\alpha\ co\beta\ +\sin\alpha\ \sin\ \beta cos α c o β + sin α sin β

cos ⁡ α c o β − sin ⁡ α sin ⁡ β \cos\alpha\ co\beta\ -\sin\alpha\ \sin\ \beta cos α c o β − sin α sin β

cos ⁡ ( α − β ) = \cos\left(\alpha-\beta\right)= cos ( α − β ) =

cos ⁡ α c o β + sin ⁡ α sin ⁡ β \cos\alpha\ co\beta\ +\sin\alpha\ \sin\ \beta cos α c o β + sin α sin β

sin ⁡ α cos ⁡ β + sin ⁡ β cos ⁡ α \sin\alpha\ \cos\beta+\sin\beta\ \cos\alpha sin α cos β + sin β cos α

sin ⁡ α cos ⁡ β − sin ⁡ β cos ⁡ α \sin\alpha\ \cos\beta-\sin\beta\ \cos\alpha sin α cos β − sin β cos α

cos ⁡ α c o β − sin ⁡ α sin ⁡ β \cos\alpha\ co\beta\ -\sin\alpha\ \sin\ \beta cos α c o β − sin α sin β

cos ⁡ ( α + β ) = \cos\left(\alpha+\beta\right)= cos ( α + β ) =

cos ⁡ α c o β − sin ⁡ α sin ⁡ β \cos\alpha\ co\beta\ -\sin\alpha\ \sin\ \beta cos α c o β − sin α sin β

sin ⁡ α cos ⁡ β + sin ⁡ β cos ⁡ α \sin\alpha\ \cos\beta+\sin\beta\ \cos\alpha sin α cos β + sin β cos α

sin ⁡ α cos ⁡ β − sin ⁡ β cos ⁡ α \sin\alpha\ \cos\beta-\sin\beta\ \cos\alpha sin α cos β − sin β cos α

cos ⁡ α c o β + sin ⁡ α sin ⁡ β \cos\alpha\ co\beta\ +\sin\alpha\ \sin\ \beta cos α c o β + sin α sin β

tan ⁡ ( α + β ) = \tan\left(\alpha+\beta\right)= tan ( α + β ) =

tan ⁡ α + tan ⁡ β 1 − tan ⁡ α tan ⁡ β \frac{\tan\alpha+\tan\beta}{1-\tan\alpha\tan\beta} 1 − tan α tan β tan α + tan β

tan ⁡ α + tan ⁡ β 1 + tan ⁡ α tan ⁡ β \frac{\tan\alpha+\tan\beta}{1+\tan\alpha\tan\beta} 1 + tan α tan β tan α + tan β

tan ⁡ α − tan ⁡ β 1 − tan ⁡ α tan ⁡ β \frac{\tan\alpha-\tan\beta}{1-\tan\alpha\tan\beta} 1 − tan α tan β tan α − tan β

tan ⁡ α − tan ⁡ β 1 + tan ⁡ α tan ⁡ β \frac{\tan\alpha-\tan\beta}{1+\tan\alpha\tan\beta} 1 + tan α tan β tan α − tan β

tan ⁡ ( α − β ) = \tan\left(\alpha-\beta\right)= tan ( α − β ) =

tan ⁡ α − tan ⁡ β 1 + tan ⁡ α tan ⁡ β \frac{\tan\alpha-\tan\beta}{1+\tan\alpha\tan\beta} 1 + tan α tan β tan α − tan β

tan ⁡ α + tan ⁡ β 1 + tan ⁡ α tan ⁡ β \frac{\tan\alpha+\tan\beta}{1+\tan\alpha\tan\beta} 1 + tan α tan β tan α + tan β

tan ⁡ α − tan ⁡ β 1 − tan ⁡ α tan ⁡ β \frac{\tan\alpha-\tan\beta}{1-\tan\alpha\tan\beta} 1 − tan α tan β tan α − tan β

tan ⁡ α + tan ⁡ β 1 − tan ⁡ α tan ⁡ β \frac{\tan\alpha+\tan\beta}{1-\tan\alpha\tan\beta} 1 − tan α tan β tan α + tan β

cos ⁡ 80 ° cos ⁡ 20 ° + sin ⁡ 80 ° sin ⁡ 20 ° \cos80\degree\cos20\degree+\sin80\degree\sin20\degree cos 8 0 ° cos 2 0 ° + sin 8 0 ° sin 2 0 ° Вычислите:

3 2 \frac{\sqrt{3}}{2} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

cos ⁡ 100 ° \cos\ 100\degree cos 1 0 0 °

2 2 \frac{\sqrt{2}}{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

cos ⁡ 12 ° cos ⁡ 18 ° − sin ⁡ 12 ° sin ⁡ 18 ° \cos12\degree\cos18\degree-\sin12\degree\sin18\degree cos 1 2 ° cos 1 8 ° − sin 1 2 ° sin 1 8 ° Вычислите:

3 2 \frac{\sqrt{3}}{2} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

cos ⁡ 6 ° \cos\ 6\degree cos 6 °

2 2 \frac{\sqrt{2}}{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

sin ⁡ 80 ° cos ⁡ 20 ° + cos ⁡ 80 ° sin ⁡ 20 ° \sin80\degree\cos20\degree+\cos80\degree\sin20\degree sin 8 0 ° cos 2 0 ° + cos 8 0 ° sin 2 0 ° Вычислите:

sin ⁡ 100 ° \sin\ 100\degree sin 1 0 0 °

3 2 \frac{\sqrt{3}}{2} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 2 \frac{\sqrt{2}}{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

sin ⁡ 88 ° cos ⁡ 28 ° − cos ⁡ 88 ° sin ⁡ 28 ° \sin88\degree\cos28\degree-\cos88\degree\sin28\degree sin 8 8 ° cos 2 8 ° − cos 8 8 ° sin 2 8 ° Вычислите:

3 2 \frac{\sqrt{3}}{2} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

sin ⁡ 116 ° \sin\ 116\degree sin 1 1 6 °

2 2 \frac{\sqrt{2}}{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Вычисли tan ⁡ 31 ° + tan ⁡ 14 ° 1 − tan ⁡ 31 ° tan ⁡ 14 ° \frac{\tan31\degree+\tan14\degree}{1-\tan31\degree\tan14\degree} 1 − tan 3 1 ° tan 1 4 ° tan 3 1 ° + tan 1 4 °

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 3 \frac{\sqrt{3}}{3} 3 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Вычислите, не пользуясь калькулятором sin ⁡ 105 ° = \sin\ 105\degree= sin 1 0 5 ° =

6 + 2 4 \frac{\sqrt{6}+\sqrt{2}}{4} 4 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 2 \frac{\sqrt{2}}{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 − 6 4 \frac{\sqrt{2}-\sqrt{6}}{4} 4 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 4 \frac{\sqrt{3}}{4} 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Вычислите, не пользуясь калькулятором cos ⁡ 105 ° = \cos\ 105\degree= cos 1 0 5 ° =

2 − 6 4 \frac{\sqrt{2}-\sqrt{6}}{4} 4 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 + 2 4 \frac{\sqrt{6}+\sqrt{2}}{4} 4 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 2 \frac{\sqrt{2}}{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 4 \frac{\sqrt{3}}{4} 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Вычисли sin ⁡ 15 ° cos ⁡ 15 ° \sin15\degree\cos15\degree sin 1 5 ° cos 1 5 °

3 2 \frac{\sqrt{3}}{2} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Основные тригонометрические формулы

10th Grade

•

20 Qs

Similar activities

Repaso sesión 8

9th - 12th Grade

•

15 Qs

soal pas MTK (UN BAB awal)

9th - 12th Grade

•

15 Qs

Ulangan Harian 2 kelas X IPA 2

10th Grade

•

20 Qs

PENILAIAN HARIAN 1 KD 3.8 & 3.9 Vers 1

10th Grade

•

20 Qs

TRIGONOMETRI

10th Grade

•

15 Qs

การหาค่าไซน์และโคไซน์

9th - 12th Grade

•

15 Qs

Evaluación Trigonometria

10th Grade

•

20 Qs

ÁNGULOS NOTABLES 5to B SEC 😃

10th - 12th Grade

•

20 Qs

Основные тригонометрические формулы

Quiz

•

Mathematics

•

10th Grade

•

Practice Problem

•

Medium

Jaana Pitšugina

Used 20+ times

FREE Resource

$\frac{\tan\alpha-\tan\beta}{1+\tan\alpha\tan\beta}$

$\frac{\tan\alpha+\tan\beta}{1-\tan\alpha\tan\beta}$

Create a free account and access millions of resources

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

17 questions

Стереометрия: параллельность и перпендикулярность

Quiz

•

10th - 12th Grade

15 questions

PROBABILIDAD 4º ESO

Quiz

•

8th - 10th Grade

15 questions

Graphs of Trigonometric Functions 1

Quiz

•

10th Grade - Professi...

20 questions

Math 10C Labelling Right Triangles

Quiz

•

8th - 11th Grade

15 questions

Trig Values of Special Angles

Quiz

•

9th - 12th Grade

17 questions

SohCahToa (1)

Quiz

•

9th - 10th Grade

22 questions

Trigonometric Ratios

Quiz

•

9th - 12th Grade

15 questions

Conocimientos Previos

Quiz

•

5th - 10th Grade

Popular Resources on Wayground

10 questions

Honoring the Significance of Veterans Day

Interactive video

•

6th - 10th Grade

9 questions

FOREST Community of Caring

Lesson

•

1st - 5th Grade

10 questions

Exploring Veterans Day: Facts and Celebrations for Kids

Interactive video

•

6th - 10th Grade

19 questions

Veterans Day

Quiz

•

5th Grade

14 questions

General Technology Use Quiz

Quiz

•

8th Grade

25 questions

Multiplication Facts

Quiz

•

5th Grade

15 questions

Circuits, Light Energy, and Forces

Quiz

•

5th Grade

19 questions

Thanksgiving Trivia

Quiz

•

6th Grade

Discover more resources for Mathematics

34 questions

Geometric Terms

Quiz

•

9th - 12th Grade

16 questions

Proportional Relationships And Constant Of Proportionality

Quiz

•

7th - 12th Grade

20 questions

Simplifying Radicals

Quiz

•

10th Grade

15 questions

Identify Triangle Congruence Criteria

Quiz

•

9th - 12th Grade

16 questions

Function or Non-Function?

Quiz

•

8th - 10th Grade

13 questions

Reading And Writing Numerical Expression

Quiz

•

6th - 12th Grade

56 questions

CCG 2.2.3 Area

Quiz

•

9th - 12th Grade

20 questions

Triangle Congruence

Quiz

•

9th - 10th Grade

Основные тригонометрические формулы

20 questions

$\sin\left(\alpha+\beta\right)=$

$\sin\left(\alpha-\beta\right)=$

$\cos\left(\alpha-\beta\right)=$

$\cos\left(\alpha+\beta\right)=$

$\sin2\alpha=$

$\cos2\alpha=$

$\tan\left(\alpha+\beta\right)=$

$\tan\left(\alpha-\beta\right)=$

$\tan\ 2\alpha=$

$\cos80\degree\cos20\degree+\sin80\degree\sin20\degree$ Вычислите:

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Основные тригонометрические формулы

20 questions

sin⁡(α+β)=\sin\left(\alpha+\beta\right)=sin(α+β)=

sin⁡(α−β)=\sin\left(\alpha-\beta\right)=sin(α−β)=

cos⁡(α−β)=\cos\left(\alpha-\beta\right)=cos(α−β)=

cos⁡(α+β)=\cos\left(\alpha+\beta\right)=cos(α+β)=

sin⁡2α=\sin2\alpha=sin2α=

cos⁡2α=\cos2\alpha=cos2α=

tan⁡(α+β)=\tan\left(\alpha+\beta\right)=tan(α+β)=

tan⁡(α−β)=\tan\left(\alpha-\beta\right)=tan(α−β)=

tan⁡ 2α=\tan\ 2\alpha=tan 2α=

cos⁡80°cos⁡20°+sin⁡80°sin⁡20°\cos80\degree\cos20\degree+\sin80\degree\sin20\degreecos80°cos20°+sin80°sin20° Вычислите:

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

$\sin\left(\alpha+\beta\right)=$

$\sin\left(\alpha-\beta\right)=$

$\cos\left(\alpha-\beta\right)=$

$\cos\left(\alpha+\beta\right)=$

$\sin2\alpha=$

$\cos2\alpha=$

$\tan\left(\alpha+\beta\right)=$

$\tan\left(\alpha-\beta\right)=$

$\tan\ 2\alpha=$

$\cos80\degree\cos20\degree+\sin80\degree\sin20\degree$ Вычислите: