Graphing in POINT-SLOPE Form ~ HONORS

Graphing in POINT-SLOPE Form ~ HONORS

8th Grade

26 Qs

quiz-placeholder

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Graphing in POINT-SLOPE Form ~ HONORS

Graphing in POINT-SLOPE Form ~ HONORS

Assessment

Quiz

Mathematics

8th Grade

Medium

CCSS
HSA.CED.A.2, 8.EE.B.5, 8.EE.B.6

+3

Standards-aligned

Created by

Lisa Carreon

Used 10+ times

FREE Resource

26 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Write the equation in point-slope form of the line that passes through the given point and has the given slope.


(4, -7); m = -1/4

y + 7 = -1/4(x - 4)

y - 4 = -1/4(x + 7)

y + 7 = 4(x - 4)

y - 7 = -1/4(x - 4)

Tags

CCSS.HSA.CED.A.2

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Write the equation in point-slope form of the line that passes through the given point and has the given slope:


(-2, -1); m= -3

y + 1 = -3(x - 2)

y + 1 = -3(x + 2)

y - 1 = 3(x - 1)

y + 2 = -3(x + 1)

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GPE.B.5

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Write the equation in point-slope form of the line that passes through the given point and has the given slope:


(-2, -1); m= -3

y + 1 = -3(x - 2)

y + 1 = -3(x + 2)

y - 1 = 3(x - 1)

y + 2 = -3(x + 1)

Tags

CCSS.HSA.CED.A.2

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Write the equation of the line in Point-Slope Form that goes through the point (10,5) and has a slope of -3

y - 5 = -3(x - 10)

y= -3x + 35

y + 5= -3(x + 10)

y= -3x - 35

Tags

CCSS.HSA.CED.A.2

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which of these represents point-slope form of a linear equation?

y - y1 = m(x - x1)

Ax + By = C

y = mx + b

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Given y + 6 = 10( x - 9) , what is the point used to write this equation?

(10, 9)

(6, -9)

(-6, 9)

(9, -6)

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the equation of the line in point slope form given a slope of and the point ( -4, 7)

y - ⅔ = -4( x - 7)

y +7 = ⅔(x - 4)

y - 7 = ⅔(x + 4)

y +7 = ⅔(x - 4)

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