Sum and Difference of Cubes

Factor:   x³ + 1

• (x + 1)³
• (x+1)(x² - x + 1)
• (x - 1) (x² + x - 1)
• (x + 1)(x² - 2x + 1)

Tags

CCSS.HSA.APR.C.4

Factor: 8x³ - 1

• (2x - 1)(4x² + 2x + 1)
• (2x + 1)(4x² - 2x + 1)
• (2x - 1)(4x² - 2x - 1)
• (2x + 1)(4x² +2x + 1)

Tags

CCSS.HSA.APR.C.4

Factor:  27x³ + 8

• (3x + 2)(9x² - 6x + 4)
• (9x + 2)(3x² + 18x + 4)
• (3x²+4)(9x + 2)
• (27x + 8)(x² - 216x + 64)

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Complete the formula
a³-b³=

• (a-b)(a²+ab+b²)
• (a+b)(a²-ab+b²)
• (a-b)(a²-ab+b²)
• (a+b)(a²+ab+b²)

Tags

CCSS.6.EE.A.2C

Factor
27x³-64

• (3x-4)(9x²+12x+16)
• (3x-4)(9x²-12x+16)
• (3x+4)(9x²-12x+16)
• (3x+4)(9x²+12x+16)

Tags

CCSS.HSA.APR.C.4

Level 2 Question 11
64-27a³

• (4-3a)(9a²+12a+16)
• (3a-4)(3a²+12a+16)
• (4-3a)(3a²+12a+16)
• (4-3a)³

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Fully Factor the Following
8x³-27

• (2x+3)(4x²-6x+9)
• (2x-3)(4x²+6x+9)
• (2x-3)(4x²+6x-9)
• (2x-3)(2x²+6x+9)

Tags

CCSS.HSA.APR.C.4

WHAT FACTORING TECHNIQUE YOU HAVE TO USE TO SOLVE FOR THE FACTORS OF   27X³-343? 

• DIFFERENCE OF TWO CUBES
• DIFFERENCE OF TWO SQUARES 
• FACTORING BY GCF 

Tags

CCSS.HSA.SSE.A.2

Complete the formula

a³+b³=

• (a-b)(a²+ab+b²)

• (a+b)(a²-ab+b²)

• (a-b)(a²-ab+b²)

• (a+b)(a²+ab+b²)

Tags

CCSS.6.EE.A.2C

Which number is both a perfect square and a perfect cube?

• 64

• 27

• 81

• 16

Tags

CCSS.6.EE.A.1