Apply Chord Properties

Apply Chord Properties

9th - 12th Grade

12 Qs

quiz-placeholder

Similar activities

Properties of Chord

Properties of Chord

9th Grade

9 Qs

Chord Properties

Chord Properties

8th - 12th Grade

14 Qs

Apply Properties of Chords Geometry

Apply Properties of Chords Geometry

10th Grade - University

15 Qs

Geometry CP - Week 15 (Intro to Circles)

Geometry CP - Week 15 (Intro to Circles)

10th Grade

17 Qs

9-1 through 9-5 Quiz

9-1 through 9-5 Quiz

8th - 11th Grade

10 Qs

Circle Vocab

Circle Vocab

9th - 10th Grade

10 Qs

Circles Vocabulary and Notation

Circles Vocabulary and Notation

9th - 11th Grade

10 Qs

Arc Measures in Circles

Arc Measures in Circles

9th - 12th Grade

12 Qs

Apply Chord Properties

Apply Chord Properties

Assessment

Quiz

Mathematics

9th - 12th Grade

Medium

CCSS
HSG.C.B.5, HSG.CO.C.9, HSG.C.A.2

Standards-aligned

Created by

Ally Mcalister

Used 154+ times

FREE Resource

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Use the diagram of Circle A for the following question.
If BECD\overline{BE}\cong\overline{CD} , then what can you determine about the arc measures?
(Hint: Use Chord Theorem #1)

 measure of arc BE + measure of arc CD= 360measure\ of\ arc\ BE\ +\ measure\ of\ arc\ CD=\ 360^{\circ}  

 measure of arc BEmeasure of arc CDmeasure\ of\ arc\ BE\cong measure\ of\ arc\ CD  

 measure of arc BCmeasure of arc EDmeasure\ of\ arc\ BC\cong measure\ of\ arc\ ED  

Not enough information

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Use Circle A for the following problem.  
If measure arc BD is  125125^{\circ} , then what is the measure of arc CD? 
(Hint: Use Chord Theorem #1)

 360360^{\circ}  

 140140^{\circ}  

 235235^{\circ}  

 250250^{\circ}  

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Use circle A to answer the following questions. 

If measure of arc BC is  8080^{\circ} . Find the measure of arc CD.
Hint: Use the Chord Theorem #1)

 140140^{\circ}  

 280280^{\circ}  

 8080^{\circ}  

 250250^{\circ}  

Tags

CCSS.HSG.C.B.5

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

If BDDC\overline{BD}\cong\overline{DC} and  EF  BC\overline{EF}\ \perp\ \overline{BC} , what conclusions can say about  EF\overline{EF}  ? 
(Hint: Use Chord Theorem #2)

 \overline{EF}  is the radius of circle A

 \overline{EF}  is a secant line of circle A

 EF\overline{EF}  is the diameter of circle A

 \overline{EF}  is the tangent line of circle A

Tags

CCSS.HSG.CO.C.9

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

True or False?
If EF\overline{EF} is a diameter to Circle A, then  BD DC\overline{BD}\cong\ \overline{DC}  EF  BC\overline{EF}\ \perp\ \overline{BC}  measure of arc BE measure of arc CE.measure\ of\ arc\ BE\cong\ measure\ of\ arc\ CE.  
(Hint: Use Chord Theorem #3)

True

False

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Determine the value of x and y.

x=64 x=64^{\circ\ } and y=4y=4

x=4x=4 and y=64y=64^{\circ}

x=116x=116^{\circ} and y=4y=4

296296^{\circ} and y=4

Tags

CCSS.HSG.C.A.2

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Use the diagram of circle A.

Which expression and deductive reasoning can be used to find the value of y?

2y+1= 5x182y+1=\ 5x-18 because if a diameter is perpendicular to a chord, its the perpendicular bisector to the chord. Therefore the chord is equal to its corresponding arc.

y+3=3x4y+3=3x-4 because if a diameter is perpendicular to a chord, its the perpendicular bisector to the chord. Therefore the chord is equal to its corresponding arc.

y+4+2y+1y+4+2y+1 because if a diameter is perpendicular to a chord, its the perpendicular bisector to the chord. Therefore the chords are added together.

y+4=2y+1y+4=2y+1 because if a diameter is perpendicular to a chord, its the perpendicular bisector to the chord. Therefore the chord is divided into two equal halves.

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?