Related Rates 2

Related Rates 2

11th Grade - University

8 Qs

quiz-placeholder

Similar activities

Related Rates

Related Rates

10th - 12th Grade

10 Qs

Calculus 3.9 & 3.11 Review

Calculus 3.9 & 3.11 Review

10th Grade - University

10 Qs

Chain Rule

Chain Rule

11th - 12th Grade

12 Qs

Calculus Related Rates Practice

Calculus Related Rates Practice

9th - 12th Grade

11 Qs

A Growing Sponge

A Growing Sponge

11th Grade

5 Qs

5.a Chain Rule

5.a Chain Rule

11th - 12th Grade

9 Qs

Modelos lineales Parte 1

Modelos lineales Parte 1

University

10 Qs

Ordinary Differential Equations and Limits (G12)

Ordinary Differential Equations and Limits (G12)

12th Grade - University

6 Qs

Related Rates 2

Related Rates 2

Assessment

Quiz

Mathematics

11th Grade - University

Medium

CCSS
HSA.CED.A.2, HSG.GMD.A.1, HSF.BF.A.1

+3

Standards-aligned

Created by

P Bruner

Used 78+ times

FREE Resource

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Oil spilled from a tanker spreads in a circle whose circumference increases at a rate of 40 ft/sec. How fast is the area of the spill increasing when the circumference of the circle is 100π ft?


What equation(s) should be used?

A=πr2 and C=2πrA=πr^2\ \ and\ \ C=2πr

C=2πrC=2πr

A=πr2A=πr^2

A=πr2 and C =πdA=πr^2\ \ and\ \ \ C\ =πd

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GMD.A.1

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Oil spilled from a tanker spreads in a circle whose circumference increases at a rate of 40 ft/sec. How fast is the area of the spill increasing when the circumference of the circle is 100π ft?

What rate is given in the problem?

 dCdt=40\frac{dC}{dt}=40 

 drdt=40\frac{dr}{dt}=40 

 dAdt=40\frac{dA}{dt}=40 

 dπdt=40\frac{dπ}{dt}=40 

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.SSE.A.1

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Oil spilled from a tanker spreads in a circle whose circumference increases at a rate of 40 ft/sec. How fast is the area of the spill increasing when the circumference of the circle is 100π ft?

What rate are we looking for and when?

 dAdt when C=100π\frac{dA}{dt}\ when\ C=100π 

 dCdt when A = 100π\frac{dC}{dt}\ when\ A\ =\ 100π 

 dAdt when A = 100π\frac{dA}{dt}\ when\ A\ =\ 100π 

 dCdt when r = 100π\frac{dC}{dt}\ when\ r\ =\ 100π 

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.CED.A.4

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the derivative of circumference with respect to time?

dCdt=2πdrdt\frac{dC}{dt}=2π\cdot\frac{dr}{dt}

dCdt=2π\frac{dC}{dt}=2π

dCdt=2πr\frac{dC}{dt}=2πr

dCdt=πdrdt\frac{dC}{dt}=π\cdot\frac{dr}{dt}

Tags

CCSS.HSG.GMD.A.1

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the derivative of area with respect to time?

dAdt=2πrdrdt\frac{dA}{dt}=2πr\cdot\frac{dr}{dt}

dAdt=2πr\frac{dA}{dt}=2πr

dAdt=πrdrdt\frac{dA}{dt}=πr\cdot\frac{dr}{dt}

dAdt=πr2drdt\frac{dA}{dt}=πr^2\cdot\frac{dr}{dt}

Tags

CCSS.HSF.BF.A.1

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Oil spilled from a tanker spreads in a circle whose circumference increases at a rate of 40 ft/sec. How fast is the area of the spill increasing when the circumference of the circle is 100π ft?

What is the length of the radius when the circumference is 100π ft?

 r=50 ftr=50\ ft 

 r=100 ftr=100\ ft 

 r=50ftr=\sqrt{50}ft 

cannot be determined

Tags

CCSS.HSA.SSE.A.1

CCSS.HSG.GMD.A.1

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Oil spilled from a tanker spreads in a circle whose circumference increases at a rate of 40 ft/sec. How fast is the area of the spill increasing when the circumference of the circle is 100π ft?

At what rate is the radius changing when the circumference is 100π ft?

 drdt=20π\frac{dr}{dt}=\frac{20}{π} 

 drdt=50π\frac{dr}{dt}=\frac{50}{π} 

 drdt=50\frac{dr}{dt}=50 

 drdt=20\frac{dr}{dt}=20  

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.CED.A.2

CCSS.HSA.SSE.A.1

CCSS.HSG.GMD.A.1

8.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Oil spilled from a tanker spreads in a circle whose circumference increases at a rate of 40 ft/sec. How fast is the area of the spill increasing when the circumference of the circle is 100π ft?

 dAdt=2000 ft2sec\frac{dA}{dt}=2000\ \frac{ft^2}{\sec} 

 dAdt=40 ft2sec\frac{dA}{dt}=40\ \frac{ft^2}{\sec} 

 dAdt=100 ft2sec\frac{dA}{dt}=100\ \frac{ft^2}{\sec} 

 dAdt=200 ft2sec\frac{dA}{dt}=200\ \frac{ft^2}{\sec}  

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.SSE.A.1

CCSS.HSG.GMD.A.1