5th Solve Quadratics by Factoring

Solve for X:

(x-5)(x+6)=0

• {5,5 }

• { -5,-5 }

• { -5,-6 }

• {5,-6 }

Tags

CCSS.HSA-REI.B.4B

Solve for x: x(x-3)(x-4) = 0

• {0,3,4 }

• {3,4 }

• { 0,-3,-4 }

• { }

Tags

CCSS.HSA-REI.B.4B

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA.REI.B.4

Which equation matches these solutions? x=5,-7

• (x+5)(x-7)=0
• (x-5)(x+7)=0
• (x+5)(x+7)=0
• (x-5)(x-7)=0

Tags

CCSS.HSA-REI.B.4B

• -2, 4
• -8
• ±8
• No real solution

Tags

CCSS.HSA-REI.B.4B

Use the quadratic formula to solve 2x² + 2x - 12?

• -2, 3
• 2, 3
• 2, -3
• -2, -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

• -4, 2
• -2, 4
• -16
• -4

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

Convert x²+6x+9 to factored form and identify the solution.

• (x+3)(x+3); x=-3
• (x+4)(x+5); x=-4, -5
• (x-3)(x-3); x=3
• Not factorable

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

Find the zeros of this quadratic.

• b=4/5, b=3
• b=4, b=-3
• b=1/5, b=3
• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

What are the factors AND solutions of x² + 2x – 3 = 0

• (x - 2)(x + 1); x=2, x=-1
• (x + 1)(x - 3); x=-1, x=3
• (x + 2)(x - 1); x=-2, x=1
• (x - 1)(x + 3); x=1, x=-3

Tags

CCSS.HSA-REI.B.4B