Completing the Square

What is the first step to solving THIS equation by completing the square?
a² + 10a + 21 = 0

• Set the equation equal to zero
• Divide 10 by 2 and add the result to both sides
• Add a² and 10a together
• Subtract the 21

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.4

When factoring
x² - 4x + 4 = 20,
what goes in the blank?
(x - __ )² = 20

• 4
• 2
• 8
• 20

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Complete the Square

x² + 6x - 5

• (x + 3)² = 5

• (x + 6)² = 9

• (x + 3)² = 14

• (x + 6)² = 14

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Given: y = 2(x - 5) + 6, the vertex is

• (2,-5)
• (-5,6)
• (2,6)
• (5,6)

Tags

CCSS.HSA.REI.D.10

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

A parabola has a vertex at (-3,2). Where is the axis of symmetry?

• y = -2
• x = 3
• x = -3
• y = 2

Does the graph of
-2(x + 5) + 2
have a minimum or a maximum?

• Minimum
• Maximum
• It has neither.
• It has both.

Tags

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

Convert to vertex form.

• y=3(x+1)² - 8
• y=3(x-1) ² - 8
• y=3(x+2)² - 8
• y=3(x-2)² - 8

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Convert to vertex form.

• y=-2(x+12)² - 67
• y=-2(x-12)² - 67
• y=-2(x-6)² - 67
• y=-2(x+6)² - 67

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Convert to vertex form.

• y=1/3(x+3)² - 29
• y=1/3(x-3)² - 29
• y=1/3(x-9)² - 29
• y=1/3(x+9)² - 29

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Which of the following equations shows the vertex form of a quadratic?

• x = -b/2a
• x = (-b ±√b² - 4ac)/2a
• y = ax² + bx + c
• y = a(x - h)² + k

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3