Elimination Using Addition and Subtraction

Solve the system by elimination.  

−8x − 10y = 20
−8x − 6y = −4 

• Infinite number of solutions  
• (6, 5) 
• (−6, −5) 
• (5, −6) 

Tags

CCSS.8.EE.C.8B

Solve using elimination. 
 4x + 8y = 20
-4x + 2y = -30

• (-7,1)
• (2,-5)
• (-2,5)
• (7,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination:
4x+9y=28
-4x-y=-28

• (-7,0)
• (6,0)
• (-6,0)
• (7,0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by elimination. 
−4x − 4y = 0
4x + 4y = 0 

• (−6, −4) 
• Infinitely many solutions 
• (−6, 10) 
• No Solution 

Tags

CCSS.8.EE.C.8B

Find x and y using the elimination method
2x+3y=7
2x+7y=11

• (-2, -1)
• Infinitely Many Solution 
• (2, 1)
• No Solution 

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

The school that Stefan goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 3 senior citizen tickets and 1 child ticket for a total of $38. The school took in $52 on the second day by selling 3 senior citizen tickets and 2 child tickets. Which equations represents the system that could be used? 

• 1s + 3c = 38
  2s + 3c = 52
• 3s + 1c = 38
  3s + 2c = 52
• s + c = 38
  s + c = 52
• 3s + 3c = 38
  1s + 2c = 52

Tags

CCSS.HSA.CED.A.3

Last season two running backs on the Steelers football team rushed a combined total of 1550 yards.  One rushed 4 times as many yards as the other.  Let x and y represent the number of yards each individual player rushed. Which system of equations could be used? 

• x + y = 1550
  y  = 4x
• x + y = 1550
  y = x + 4
• y - x = 1550
  y = 4x
• y = 1550 + x
  y = x + 4

Tags

CCSS.8.EE.C.8C

4)  -6x+5y=1
           6x+4y=-10

• (1,1)
• (-1,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve using elimination. 
 4x + 8y = 20
-4x + 2y = -30

• (-7,1)
• (2,-5)
• (-2,5)
• (7,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination:
3x+7y=23

-3x-7y=-17

• No solution
• ARN
• (-3,3)
• (3,3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6