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Concentration Calculations

Concentration Calculations

Assessment

Presentation

Chemistry

9th - 12th Grade

Hard

NGSS
HS-PS1-7

Standards-aligned

Created by

Raechel Mendelsohn

Used 6+ times

FREE Resource

13 Slides • 7 Questions

1

Concentration Calculations

Working through the steps

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2

Why is Ms. Mendelsohn making us do these calculations!?!?!

The perfect cup of coffee (or tea) is very important. Which the next video to learn what coffee has to do with it.

3


4

Working through a word problem

Get out your science notebook and something to write with.

5

Pb(NO3)2 + NaOH -> ions and a ppt

Complete the chemical equation

6

Multiple Choice

What were your products?

1

NO3- + Na+ + Pb(OH)2

2

NO3- + Na+ + PbOH

3

NaNO3 + Pb(OH)2

7

You are informed that 42 mg of Pb(OH)2 precipitate formed, calculate the starting molarity of Pb(NO3)2 in 50 mL of solution.

What is this telling us?

  • We have 42 mg of solid Pb(OH)2 formed in a 50 mL solution

  • This is a concentration of mg/mL

  • We need to find the number of moles in the 50 mL

8

42 mg of Pb(NO3)2 needs to be converted to something usable. Remember our goal is moles.

How will we do this?

9

Multiple Choice

To convert your 42 mg of Pb(NO3)to moles, you should first convert your mg to g. What is the correct set-up?

1


42 mg ×1000 mg1 g42\ mg\ \times\frac{1000\ \ mg}{1\ g}

2

42 mg ×1 g1000 mg42\ mg\ \times\frac{1\ g}{1000\ mg}

3

421000\frac{42}{1000}

4

42 ×100042\ \times1000

10

Now look back at your original equation.

Pb(NO3)2 + NaOH -> ions and a ppt.

We have 42 mg Pb(NO3)2.

What is the amount of Pb(NO3)2 in grams?

11

Fill in the Blank

How many grams of Pb(NO3)2 do you have?

12

Convert your grams of Pb(NO3)2 to moles

  • Find your molar mass from the periodic table

  • Set-up your calculation to convert your grams to moles using the molar mass

13

Multiple Choice

What is the molar mass of Pb(NO3)2Pb\left(NO_3\right)_2  ?

1

 331.208 gmol\frac{331.208\ g}{mol} 

2

241.214 mol

3

 331.2 gmol\frac{331.2\ g}{mol} 

4

331.2 mol

14

Now you have the molar mass, AND you have your mass of Pb(NO3)2 in grams.

How many moles do you have?

15

Multiple Choice

How many moles of Pb(NO3)2 are in 0.042 g ?

1

0.000127 mol

(aka 1.27 x 10-4 mol)

2

0.0126 mol

(aka 1.26 x 103 mol)

3

126 mol

(aka 1.26 x 102 mol

16

Looking back:

Given that 42 mg of Pb(OH)2 precipitate formed, calculate the moles of Pb(NO3)2 in 50 mL of solution.

You have your 0.000127 mol of Pb(NO3)2 and now you need to put it in 50 mL of solution.

17

Convert your units so that you have the proper units of moles/Liter

You currently have mol/mL

18

Multiple Select

What is a good set-up for converting mol/mL to mol/L?

1

molmL × 1000 ml1 L = 1000 molL\frac{mol}{mL}\ \times\ \frac{1000\ ml}{1\ L}\ =\ \frac{1000\ mol}{L}

2

molmL×1 L1000 mL = molL1000 mL2\frac{mol}{mL}\times\frac{1\ L}{1000\ mL}\ =\ \frac{mol\cdot L}{1000\ mL^2}

19

Calculate the final molarity of your Pb(NO3)2

20

Multiple Choice

Calculate the concentration of Pb(NO3)2 in your solution.

1

0.00254 M

2

0.0254 M

3

0.0827 M

Concentration Calculations

Working through the steps

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